我有一个内置到index.html的html联系表单，然后我有一个mail.php文件，它发送邮件并使用一些Javascript。当我填写表格并提交时，我已将其编码为发送邮件，然后弹出一个成功消息框，然后重定向回index.html。
我希望将表单替换为成功消息，以避免页面刷新并避免弹出消息框。
来自index.html的表单：
<form action="mail.php" method="POST">
<div class="row uniform">
<div class="6u 12u$(xsmall)">
<input type="text" name="name" id="name" value="" placeholder="Name" />
</div>
<div class="6u$ 12u$(xsmall)">
<input type="email" name="email" id="email" value="" placeholder="Email" />
</div>
<div class="12u$">
<!--<div class="select-wrapper">
</div>-->
</div>
<div class="12u$">
<textarea name="message" id="message" placeholder="Enter your message" rows="6"></textarea>
</div>
<center><div class="g-recaptcha" data-sitekey=""></div></center>
<div class="12u$">
<ul class="actions">
<li><input type="submit" value="Send Message" class="special" /></li>
<li><input type="reset" value="Reset" /></li>
</ul>
</div>
</div>
</form>
删除了php文件，电子邮件地址和重新访问令牌，原因很明显：
<?php $name = $_POST['name'];
$email = $_POST['email'];
$message = $_POST['message'];
$formcontent = "From: $name \n email: $email \n Message: $message";
$recipient = 'email address here';
$subject = 'Message from Website';
$mailheader = "From: $email \r\n";
$captcha;
{
if(isset($_POST['g-recaptcha-response']))
{
$captcha=$_POST['g-recaptcha-response'];
}
if(!$captcha)
{
echo '<script language="javascript">';
echo 'alert("Please check the Captcha")';
echo '</script>';
exit;
}
$response=file_get_contents("https://www.google.com/recaptcha/api/siteverify?secret=&response=".$captcha."&remoteip=".$_SERVER['REMOTE_ADDR']);
if($response.success==false)
{
echo '<h2>Please do not try and spam here.</h2>';
}else
{
mail($recipient, $subject, $formcontent, $mailheader) or die("Error!");
echo '<script language="javascript">';
echo 'alert("Your Message successfully sent, we will get back to you ASAP.");';
echo 'window.location.href="index.html";';
echo '</script>';
}
} ?>
这是我实际看过的主题：
答案 0 :(得分：3)
做所有事情的最佳方法是使用ajax。在你的html中加入jquery。
将表单放在包装器div
中<div class="something">
<!-- your form here -->
</div>
通过ajax提交表单，而不是使用基本表单提交
//"idform" is the id of the form
$("#idForm").submit(function() {
var url = "path/to/your/script.php"; // the script where you handle the form input.
$.ajax({
type: "POST",
url: url,
// serialize your form's elements.
data: $("#idForm").serialize(),
success: function(data)
{
// "something" is the class of your form wrapper
$('.something').html(data);
}
});
// avoid to execute the actual submit of the form.
return false;
});
最后你需要改变的是你的PHP代码
只保留一个成功的回声
echo "Your Message successfully sent, we will get back to you ASAP.";
答案 1 :(得分：1)
您可以使用jQuery和Ajax表单提交来完成此任务。
首先，在头元素中包含jquery
<head>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.3/jquery.min.js"></script>
</head>
接下来，给你的表单一个id
<form id='mail_form' action="mail.php" method="POST">
使用id ='error'
添加某个范围<span id='error' style='color:red; font-weight:bold;'></span>
将mail.php调整为以下内容：
<?php
$success = true;
$errors = array();
$name = $_POST['name'];
$email = $_POST['email'];
$message = $_POST['message'];
$formcontent = "From: $name \n email: $email \n Message: $message";
$recipient = 'email address here';
$subject = 'Message from Website';
$mailheader = "From: $email \r\n";
$captcha = false;
if(isset($_POST['g-recaptcha-response']))
{
$captcha=$_POST['g-recaptcha-response'];
}
if(!$captcha)
{
$success = false;
array_push($errors, "Please check the captcha");
}
$response=file_get_contents("https://www.google.com/recaptcha/api/siteverify?secret=&response=".$captcha."&remoteip=".$_SERVER['REMOTE_ADDR']);
if($response.success==false)
{
$success = false;
array_push($errors, "Please do not try and spam here.");
}
if ($success)
{
mail($recipient, $subject, $formcontent, $mailheader) or die("Error!");
}
$output_array = array("success" => $success, "errors" => $errors);
echo json_encode($output_array);
?>
然后，在页面底部添加
<script>
$('#mail_form').on('submit', function(){
var dataIn = $(this).serialize(); //serialize turns the form data into a string that can be passed to mail.php. Try doing alert(dataIn); to see what it holds.
$.post( "./mail.php", dataIn )
.done(function( dataOut )
{
//dataOut holds the response from mail.php. The response would be any html mail.php outputs. I typically echo out json encoded arrays as responses that you can parse here in the jQuery.
var myArray = JSON.parse(dataOut );
if (myArray['success'] == true) //Check if it was successfull.
{
$("#mail_form").html("Congrats! We just e-mailed you!");
}
else //there were errors
{
$('#error').html(""); //Clear error span
$.each(myArray['errors'], function(i){
$('#error').append(myArray['errors'][i] + "<br>");
}
});
return false; //Make sure you do this or it will submit the form and redirect
});
</script>
答案 2 :(得分：1)
首先，您应该使用AJAX调用来提交表单。如果你坚持使用纯JS，那么脚本看起来就像这样（写在5秒内 - 可能需要一些调整）：
<script>
document.forms['yourForm'].onsubmit = function(form) { // you have to add 'name' attribute to the form and replace 'yourForm' with it
var data = ... //here you have to get all the values from form elements and store them in data object. to make less changes to the script use the elements' names as object names
if (window.XMLHttpRequest)
{
var xhReq = new XMLHttpRequest();
}
else
{
var xhReq = new ActiveXObject("Microsoft.XMLHTTP");
}
var method= 'POST')
var async = false; //you can actually set true here, it doesn't matter much in this case
var url = 'mail.php';
xhReq.open(method, url, async);
xhReq.setRequestHeader("Content-type", "application/x-www-form-urlencoded");
xhReq.setRequestHeader("X-Requested-With", "XMLHttpRequest");
xhReq.send(data);
document.getElementById("form's parent's ID goes here").innerHTML = "new content"
return false;
}
</script>
您必须从php文件中删除所有回声，因为它无论如何都不会显示。您还可以为此脚本添加更多复杂功能，例如检查邮件功能是否正常工作（通过返回php文件中的内容并检查JS中的AJAX响应）或捕获验证码错误。如果你愿意走这条路，那么在jQuery中实现起来也会非常容易。