我正在阅读.xltx,我想导出.xlsx。
protected static final String ruta = ResourcesPathEnum.ROOT.getId() + "plantillas" + File.separator;
public static final String CONTENT_TYPE = "application/vnd.openxmlformats-officedocument.spreadsheetml.sheet";
protected abstract Workbook xlsx() throws FileNotFoundException, IOException;
/**
* Genera excel
*
* @return InputStream
*/
public InputStream getFile() {
try {
ByteArrayOutputStream bos = new ByteArrayOutputStream();
try {
xlsx().write(bos);
} finally {
bos.close();
}
return new ByteArrayInputStream(bos.toByteArray());
} catch (FileNotFoundException e) {
Logger.error(e.getMessage());
} catch (IOException e) {
Logger.error(e.getMessage());
}
return null;
}
public StreamedContent getFile() {
ControllerReportSuceso aux = new ControllerReportSuceso(suceso, sucesosAvionWrapper);
return new DefaultStreamedContent(aux.getFile(), ControllerReportSuceso.CONTENT_TYPE, "parte suceso: " + suceso.getEntidad().getNumeroOrden() + ".xlsx");
}
导出时,.xlsx在打开文件时总是给我一个错误, Excel无法打开文件,因为格式或扩展名不正确。如果我将扩展名更改为.xls,我可以打开它。
我正在使用POI 3.12。
答案 0 :(得分:0)
IP = [('192.168.1.1'),
('192.168.1.1'),
('192.168.1.2'),
('192.168.1.3')]
dfIP = pd.DataFrame(IP, columns=['IP'])
dfIPdup = dfIP[dfIP.duplicated()]
#logic is we got the duplicate and now add a column and mention 'duplicate' or unique