Question

我使用了最新版本的Xcode以及最新版本的Swift。我按照link的步骤操作，但是选择器视图没有显示在模拟器中。代码如下。有人可以帮我查一下吗？非常感谢！

import UIKit

class ViewController: UIViewController, UIPickerViewDelegate {

@IBOutlet var imageView: UIImageView!

@IBOutlet var infoLabel: UILabel!

@IBOutlet var picker: UIPickerView!

//var fruits: [String] = [String]()
var fruits = ["Pick a fruit" , "Apples" , "Oranges" , "Lemons" , "Blueberries"]

override func viewDidLoad() {
    super.viewDidLoad()
    imageView.image = UIImage(named: "fruit.jpg")
   // picker.delegate = self

    // Do any additional setup after loading the view, typically from a nib.
}

override func didReceiveMemoryWarning() {
    super.didReceiveMemoryWarning()
    // Dispose of any resources that can be recreated.
}



func numberOfComponentsInPickerView(pickerView: UIPickerView) -> Int{
    return 1
}


func pickerView(pickeView: UIPickerView, numberOfRowsInCompoment component: Int) ->Int{
    return 5
}

func pickerView(pickerView: UIPickerView, titleForRow row: Int, forComponent component: Int) -> String?{
    return fruits[row]
}

func pickerView(pickerView: UIPickerView, didSelectRow row: Int, inComponent component: Int){

    var fruitSelected = fruits[row]

    switch (fruitSelected){
    case "Apples":
        imageView.image = UIImage(named: "apple.jpg")
        infoLabel.text = "These apples are red"

    case "Oranges":
        imageView.image = UIImage(named: "orange.jpg")
        infoLabel.text = "These oranges are yellow"

    case "Lemons":
        imageView.image = UIImage(named: "Lemon.jpg")
        infoLabel.text = "These lemons are green"

    case "Blueberries":
        imageView.image = UIImage(named: "Blueberry.jpg")
        infoLabel.text = "These blueberries are blue"

    default:
        imageView.image = UIImage(named: "fruit.jpg")
        infoLabel.text = "Pick a fruit"
    }
  }
}

Answer 1

假设您已在故事板中正确设置了委托和数据源，那么您的问题是方法签名不正确。请注意方法签名(pickeView: UIPickerView, numberOfRowsInCompoment component: Int)中的拼写错误。 r中pickeView中缺少m而n中使用numberOfRowsInCompoment而不是func pickerView(pickerView: UIPickerView, numberOfRowsInComponent component: Int) ->Int{ return 5 }。

尝试使用以下功能，你应该全部设置......

19 August 2015 - 10:50 am

Swift 2.1 - UIPickerView不能很好地工作

1 个答案: