如何知道属性或节点是否具有不同的命名空间?

时间:2015-10-13 00:03:27

标签: xml actionscript-3 flash

我如何知道何时遇到带有命名空间的节点?当我这样做时,是否可以提取该命名空间的名称和URL?

XML:

<s:Image xmlns:fx="http://ns.adobe.com/mxml/2009" 
         xmlns:s="library://ns.adobe.com/flex/spark" 
         xmlns:test="library://ns.test.com/flex/"

         visible="false" 
         test:locked="true" />

XML解析代码:

public static function getAttributeNames(node:XML):Array {
    var result:Array = [];
    var attributeName:String;

    for each (var attribute:XML in node.attributes()) {
        attributeName = attribute.name().toString();

        result.push(attributeName);
    }
    return result;
}

trace (result);

[0] visible
[1] library://ns.test.com/flex/::locked

我可以检查&#34; ::&#34;在字符串中,但似乎很麻烦。肯定有更好的办法。

1 个答案:

答案 0 :(得分:0)

使用来自不同但相关帖子的信息,我能够检查attribute.namespace()对象。通常没什么!但是当它具有名称空间前缀时,它将返回一个对象。

public static function getAttributeNames(node:XML):Array {
    var result:Array = [];
    var attributeName:String;

    for each (var attribute:XML in node.attributes()) {
        attributeName = attribute.name().toString();

        var attNamespace:Object = attribute.namespace();
        var a:Object = attribute.namespace().prefix     //returns prefix i.e. rdf
        var b:Object = attribute.namespace().uri        //returns uri of prefix i.e. http://www.w3.org/1999/02/22-rdf-syntax-ns#

        var c:Object = attribute.inScopeNamespaces()   //returns all inscope namespace as an associative array like above

        //returns all nodes in an xml doc that use the namespace
        var nsElement:Namespace = new Namespace(attribute.namespace().prefix, attribute.namespace().uri);

        var usageCount:XMLList = attribute..nsElement::*;
        result.push(attributeName);
    }

    return result;
}

here获得的信息。