Question

假设我有一个名为“farmstuff”的表，就像这个高度简化且看起来很奇怪的表;

id  mark        pjob        role        jobDesc 
1    1        horses        Smithy      Smith Stuff 
1    1        horses        Smithy      More Smith stuff
1    1        horses        Smithy      Even More Smith stuff
2    1        cows         Farrier      Put left front shoe on
2    1        cows         Farrier      Put right front shoe on

我的PHP阅读它是这样的：

 <?php
 $tableheader = "<table><thead><tr><th>col3</th><th>col4</th></tr></thead><tbody>";
 $sql = "SELECT id, mark,  pjob, role, jobDesc FROM farmstuff WHERE mark = 1 ORDER BY id";
     $echo($tableheader);
     foreach($found->query($sql) as $row) {
         echo ("<tr>");
     }
         echo("<td>$row[role]</td>");
         echo("<td>$row[jobDesc]</td>");
     }   echo("</tr></tbody></table>");
 ?>

我想要的是两张如下表。尽管其他变量的值，我想在id的值的变化打破表。因此，如果它的1然后第一个标题是马，如果它是2那么标题是奶牛。请记住这些是现在的表格。首先，我如何从SQL的输出中创建两个具有适当中断的表，然后如何将标签放在每个表的顶部，如下例所示？

horses
col4        col5
Smithy      Smith Stuff
Smithty     More Smith Stuff
Smithy      Even More Smith Stuff
cows
col4        col5
Farrier     Put left front shoe on
Farrier     Put right front shoe on

Answer 1

这未经过测试（更多原型），但有类似的内容：

<?php
 $tableheader = "<table><thead><tr><th>col3</th><th>col4</th></tr></thead><tbody>";
 $sql = "SELECT id, mark,  pjob, role, jobDesc FROM farmstuff WHERE mark = 1 ORDER BY id";
     $echo($tableheader);
     $lastid = '';
     foreach($found->query($sql) as $row) {
         if($lastid != $row[role]) {
           echo ("<tr><td colspan=2>$row[id]</td></tr>");
         }
         echo ("<tr>");
         echo("<td>$row[role]</td>");
         echo("<td>$row[jobDesc]</td>");
         echo("</tr>");
         $lastid = $row[role];
     }
     echo("</tbody></table>");
 ?>

一个MySQL查询中的两个表

1 个答案: