Question

我是一个相当新的PHP，我一直无法使用该表格保存内存为radioboxes，checkboxes＆amp; （下拉列表）选择列表，因此我提交或选择的数据在提交时仍然存在。

＆＃13;

		<select  name = "province[]" multiple size = "12">
				
	<?php foreach ($PROVINCES as $key => $value) {?>
   <option value = "<?php echo $value ?>"<?php (in_array('$key',$_POST['province'] ) )?'selected':'';?>><?php echo $value ?></option>				
<?php }?>
				</select>	
			<br><br>
	<label for = "status">Status(Mult Select)<font color = "red">*</font></label>
	<input type = "checkbox" name = "status[]" id = "Approved" value= "Approved"> Approved 
	<input type = "checkbox" name = "status[]" id = "Pending Application" value="Pending Application"> Pending Application 
	<input type = "checkbox" name = "status[]" id = "Active Service" value="Active Service"> Active Service 
			<br><br>
	<label for = "location">Location<font color = "red">*</font></label>
	<input type = "radio" name = "location" id = "Garage" value = "Garage"> Garage
	<input type = "radio" name = "location" id= "Attic" value = "Attic"> Attic
	<input type = "radio" name = "location" id = "House" value = "House"> House
			</fieldset>

＆＃13;

Answer 1

我的建议是使用PHP in_array函数来回显已检查的状态。此外，总是很好地查看POST参数的状态（有助于确定浏览器发送到服务器的内容）

＆＃13;

<pre><?php var_dump($_POST); ?></pre>
<input <?php if(in_array('Approved', $_POST['status'])) echo ' checked="checked"'; ?> type = "checkbox" name = "status[]" id = "Approved" value= "Approved"> Approved 
<input <?php if(in_array('Pending Application', $_POST['status'])) echo ' checked="checked"'; ?> type = "checkbox" name = "status[]" id = "Pending Application" value="Pending Application"> Pending Application

＆＃13;

希望能让你走上正轨。注意：虽然有更好的方法可用于通过PHP管理Form元素。寻找任何框架，例如Zend Framework。

表格输入内存为radioboxes，复选框和＆amp;下拉（选择）表格

1 个答案: