Question

我试图从mysql表的date列中获取所有年份和月份。预期的结果应该用在一个meny中，应该看起来像这样：

**2015**
oct
sep
aug
july
june
may
apr
mars
feb
jan
**2014**
dec
nov
oct
sep
aug
july
june
may
apr
mars
feb
jan
**2013**
dec
nov
oct
sep
aug
july
june
may
apr
mars
feb
jan

起初我试过这个：

public static function arrange(){

        $database = DatabaseFactory::getFactory()->getConnection();

        //Select all years
        $sql = "SELECT DISTINCT YEAR(date) FROM MOCK_DATA ORDER by YEAR(date) DESC";
        $query = $database->prepare($sql);
        $query->execute();
        $years = $query->fetchAll();

        //Select all months in numbers
        $sql = "SELECT DISTINCT MONTH(DATE) AS month_num FROM MOCK_DATA WHERE YEAR(DATE) = :year ORDER BY DATE DESC";
        $query = $database->prepare($sql);
        $query->execute(array(':year' => $years));
        $query->fetchAll();

         $months_int = array(
                         1=>'januari',
                         2=>'februari',
                         3=>'mars',
                         4=>'april',
                         5=>'maj',
                         6=>'juni',
                         7=>'juli',
                         8=>'agusti',
                         9=>'september',
                         10=>'oktober',
                         11=>'november',
                         12=>'december');

                $months_string = array();
                foreach($months_int as $month){
                        $months_string[] = strtr($month,$months_int);
                }

        return $months_string;
}

但我没有得到它的工作，它似乎更加“先进”然后neccesery，因为经过一个小时左右的谷歌搜索 - 我发现了这个：

SELECT DISTINCT CONCAT(MONTHNAME(date), ' ', YEAR(date)) AS `Month`
FROM MOCK_DATA
ORDER BY date DESC

来自docs。

所以，遗憾的是我无法使用该查询。但是发现那个查询认为有一个查询可以产生我正在寻找的东西！

我认为我的查询应该给我一个类似$data->years和$data->months的stdClass。所以我可以用

循环它

foreach($data->years as $years){
echo $years;
foreach($data->months as $months){
echo $months;}
}

我的问题是：是否存在mysql查询，它为我提供了当年的所有years和所有months？ 如果不是：我如何使用php执行此操作？

从表格中选择所有月份和年份

0 个答案: