框架使用"聚合目标"和" Cocoa Touch Framework"。有什么区别?

时间:2015-10-12 14:53:42

标签: ios objective-c xcode cocoa xcode7

我可以使用" Aggregate target"在XCode中创建Framework。也可以创建" Cocoa Touch Framework"在XCode 7中。

他们之间有什么区别? 在新项目中哪种方式更可取?

2 个答案:

答案 0 :(得分:1)

我更喜欢制作Cocoatouch框架。 最后,运行脚本使其成为通用框架。 你不需要把它变成聚合。

仅供参考,这是我现在使用的脚本。 我从网上找到了这个脚本。 (我不记得来源)



set -e
set +u
# Avoid recursively calling this script.
if [[ $SF_MASTER_SCRIPT_RUNNING ]]
then
exit 0
fi
set -u
export SF_MASTER_SCRIPT_RUNNING=1


# Constants
SF_TARGET_NAME=${PROJECT_NAME}
UNIVERSAL_OUTPUTFOLDER=${BUILD_DIR}/${CONFIGURATION}-universal

# Take build target
if [[ "$SDK_NAME" =~ ([A-Za-z]+) ]]
then
SF_SDK_PLATFORM=${BASH_REMATCH[1]}
else
echo "Could not find platform name from SDK_NAME: $SDK_NAME"
exit 1
fi

if [[ "$SF_SDK_PLATFORM" = "iphoneos" ]]
then
echo "Please choose iPhone simulator as the build target."
exit 0
fi

IPHONE_DEVICE_BUILD_DIR=${BUILD_DIR}/${CONFIGURATION}-iphoneos

# Build the other (non-simulator) platform
xcodebuild -project "${PROJECT_FILE_PATH}" -target "${TARGET_NAME}" -configuration "${CONFIGURATION}" -sdk iphoneos BUILD_DIR="${BUILD_DIR}" OBJROOT="${OBJROOT}" BUILD_ROOT="${BUILD_ROOT}" CONFIGURATION_BUILD_DIR="${IPHONE_DEVICE_BUILD_DIR}/arm64" SYMROOT="${SYMROOT}" ARCHS='arm64' VALID_ARCHS='arm64' $ACTION

xcodebuild -project "${PROJECT_FILE_PATH}" -target "${TARGET_NAME}" -configuration "${CONFIGURATION}" -sdk iphoneos BUILD_DIR="${BUILD_DIR}" OBJROOT="${OBJROOT}" BUILD_ROOT="${BUILD_ROOT}"  CONFIGURATION_BUILD_DIR="${IPHONE_DEVICE_BUILD_DIR}/armv7" SYMROOT="${SYMROOT}" ARCHS='armv7 armv7s' VALID_ARCHS='armv7 armv7s' $ACTION

# Copy the framework structure to the universal folder (clean it first)
rm -rf "${UNIVERSAL_OUTPUTFOLDER}"
mkdir -p "${UNIVERSAL_OUTPUTFOLDER}"
cp -R "${BUILD_DIR}/${CONFIGURATION}-iphonesimulator/${PROJECT_NAME}.framework" "${UNIVERSAL_OUTPUTFOLDER}/${PROJECT_NAME}.framework"

# Smash them together to combine all architectures
lipo -create  "${BUILD_DIR}/${CONFIGURATION}-iphonesimulator/${PROJECT_NAME}.framework/${PROJECT_NAME}" "${BUILD_DIR}/${CONFIGURATION}-iphoneos/arm64/${PROJECT_NAME}.framework/${PROJECT_NAME}" "${BUILD_DIR}/${CONFIGURATION}-iphoneos/armv7/${PROJECT_NAME}.framework/${PROJECT_NAME}" -output "${UNIVERSAL_OUTPUTFOLDER}/${PROJECT_NAME}.framework/${PROJECT_NAME}"




转到项目设置 - >构建阶段,然后单击加号按钮添加新的运行脚本。

答案 1 :(得分:0)

如果您需要支持iOS<那么你就不能使用" Cocoa Touch Framework"