由于我尝试过的代码并通过试用删除来获取返回的json内容如下 我使用的方法。
$(event.target).find('youtube-player').data('YoutubeAPI')
代码以yahoo和json格式返回给定的批量
删除未知格式
$date= YYYYMMDD;
//example '20140113'
$handle = fopen('http://finance.yahoo.com/connection/currency-converter-cache?date='.$date.'', 'r');
//sample code is http://finance.yahoo.com/connection/currency-converter-cache?date=20140208 paste the url in browser;
// use loop to get all until end of content
while (!feof($handle)) {
$contents .= fread($handle, 8192);
}
fclose($handle);
通过
"/**/YAHOO.Finance.CurrencyConverter.addConversionRates (" and ends with ");"
答案 0 :(得分:3)
我更喜欢使用file_get_contents
来html
和preg_match_all
清除json
,即:
<?php
$json = file_get_contents("http://finance.yahoo.com/connection/currency-converter-cache?date=20140113");
preg_match_all('/\((.*)\);/si', $json, $json, PREG_PATTERN_ORDER);
$json = $json[1][0];
$json = json_decode($json,true);
foreach ($json["list"]["resources"] as $resource){
echo $resource["resource"]["fields"]["date"];
echo $resource["resource"]["fields"]["price"];
echo $resource["resource"]["fields"]["symbol"];
echo $resource["resource"]["fields"]["price"];
}
注意:
我已经测试了代码,它按预期工作。