Question

我的任务是编写一个程序，提示用户输入正数，然后绘制星号块（*）以形成楼梯。第一个块的长度和宽度应该是输入的数字。下一个块应该加倍该大小，依此类推，直到显示的块数等于输入的数量。

import java.util.Scanner;
public class Lab1 {

    public static void main(String[] args) {
        Scanner keyboard = new Scanner(System.in);
        System.out.println("Enter a number of length and width of the first blocks and I will draw some stairs!");
        int number = keyboard.nextInt();
        for (int i =0; i<number; i++) {
            for (int j=0; j<number; j++) {
                System.out.print("*");
            }
            System.out.println("");
        }
    }

}

输入3的示例输出：

3

...
...
...
......
......
......
......
......
......
.........
.........
.........
.........
.........
.........
.........
.........

Answer 1

您只需要在步骤大小上添加另一个循环。

Scanner keyboard = new Scanner(System.in);
System.out.println("Enter a number of length and width of the first blocks and I will draw some stairs!");
int number = keyboard.nextInt();
for (int n = 1; n <= number; n++) { // loop over the steps
    for (int i = 0; i < n * number; i++) { // for each step, make a rectangle of length "n * number"
        for (int j = 0; j < n * number; j++) {
            System.out.print("*");
        }
        System.out.println("");
    }
}

Answer 2

此算法使用最小 for-loops和一个条件语句，因此;应该为你想要达到的目标做得很好：

import java.util.Scanner;

public class TestMain {
    public static void main(String[] args) {
        Scanner keyboard = new Scanner(System.in);
        System.out.print("Enter a number of length and width of the first blocks and I will draw some stairs! ");
        int n = keyboard.nextInt();
        int count = n;
        int temp = n;

        for (int i = 1; i<=n*n*(n+1)/2; i++) {
            for (int j=0; j<temp; j++) {
                System.out.print("*");
            }
            count++;
                if(count%temp==0) {
                    temp = temp+n;
                    count = 0;
                }
            System.out.println();
        }
    }
}

使用星号在Java建筑楼梯

2 个答案: