Question

我有一条记录，其中包含每天捕获的customerId，GroupId，amountContributed。现在我想返回一个表格，显示一个客户使用组ID提供的总金额。我之前的代码是：

if(isset($_POST["searchVal"])){
//$searchText = $_POST["searchText"];
$sDate = $_POST["sDate"];
$eDate = $_POST["eDate"];
$query = mysqli_query($connection,"SELECT custid,grpid,amountContribute FROM tab_customer_dailycontribution WHERE cast(transactionDate as date) BETWEEN '$sDate' AND '$eDate'");
if($connection->affected_rows>0){
    $c =0;$con =0.00;

while($rw = mysqli_fetch_array($query)){
    $c++;?> 
    <tr>
    <td><?php echo $c;?></td>
    <td><?php echo $rw['custid'];?></td>
    <td><?php echo $rw['grpid'];?></td>
    <?php $con+=$rw['amountContribute']; ?>
    <td><?php echo number_format($con,2);?></td>
  <?php  } ;?>
   </tr>
   <tr>

上面给出了这个表：

S/N CustomerID  Group ID    Total Contribution
    1   SC20151 SGC20151    700.00
    2   SC20151 SGC20151    500.00
    3   SC20151 SGC20151    500.00
    4   SC20152 SGC20151    500.00
    5   SC20152 SGC20151    500.00
    6   SC20152 SGC20151    500.00
    7   SC20152 SGC20151    500.00
    8   SC20152 SGC20151    500.00
    9   SC20152 SGC20151    500.00
    10  SC20152 SGC20151    500.00
    11  SC20152 SGC20151    500.00
    12  SC20152 SGC20151    500.00
    13  SC20152 SGC20151    500.00
    14  SC20153 SGC20152    1,000.00
    15  SC20153 SGC20152    1,000.00

所以，我希望输出如下表所示：

 SN        Customer ID      Group ID       Amount Conributed
    1         SC20152           SCG20151        5000
    2         SC20151           SCG20151        1200
    3         SC20153           SCG20152        2000

有人可以提供帮助。我使用groupid by customerid，amountcontributed但不工作。

Answer 1

SELECT custid, grpid, SUM(amountContribute) AS sumAmountContribute
FROM tab_customer_dailycontribution 
WHERE CAST(transactionDate AS date) BETWEEN '$sDate' AND '$eDate'"
GROUP BY custid, grpid

会为您提供所需的信息。

输出时，您必须更改数组索引：

<?php echo $rw['sumAmountContribute']; ?>

使用mysqli从数据库中选择，分组和求和结果

1 个答案: