Question

我经历了这几次并且没有任何错误，所以它可能是我的头脑。我也为你的眼睛做了什么道歉，这是我编程的第一年，并且可能犯了多个礼仪错误。

print('Befor we begin, when you are given options, I ask you to type your input as show, failure to do so will break the program and you will lose all of your progress')
def test():
    print('it has worked!')
def stats():
    global attack
    global health
    global mashealth
    global agility
    if race in ('human','Human'):
        maxatk=4
        maxagi=4
        attack = lambda:random.randint(2,maxatk)
        maxhealth = 20
        health=20
        agility = random.randint(maxagi,10)


    elif race in ('Orc','orc'):
        attack = random.randint(3,maxATK)
        maxhealth = 25
        agility = random.radint(maxAGI,10)


def main():
    while True:
        print('What would you like to do')
        print('Rest   Shop   Fight')
        answer=input('-')
        if answer in ('Rest','rest'):
            health=maxhealth
            continue

def character():
    global race
    global name
    global gender
    print('What would you like the name of your character to be?')
    name=input('-')
    print()
    print('What race will your character be?')
    print('Human   Orc   Elf')
    while True:
        race = input('-')
        if race in ('human','Human','Orc','orc','Elf','elf'):
            break
        else:
            print('Not a valid response, try again')
            continue
    print()
    print('What gender is your character')
    gender=input('-')
    print()

def goblin():
    goblinatk=1
    goblinhealth=100
    while True:
        print('You have encountered a goblin, what will you do?')
        do=input('-')
        if do == 'attack':
            damage=attack()
            goblinhealth=goblinhealth-damage
            print('You did',damage,'damage to the goblin')
            print('The goblin has',goblinhealth,'hp')
        goblinatk=lambda:random.randint(3,10)
        health=health-goblinatk
        print('the goblin did',goblinatk,'to you')
        print('you have',health,'hp')
        if goblinhealth <0:
            print('The goblin has died')
            break
        if health <0:
            print('you have died')
            break






character()
stats()
goblin()
test()

错误在这里

Traceback (most recent call last):
  File "H:\16CoFrega\Code\Python\GAME.py", line 255, in <module>
    goblin()
  File "H:\16CoFrega\Code\Python\GAME.py", line 238, in goblin
    health=health-goblinatk
UnboundLocalError: local variable 'health' referenced before assignment

Answer 1

您需要将health指定为全局变量，否则它将被视为局部变量，因为您在函数内部分配了它。示例 -

def goblin():
    global health
    goblinatk=1
    goblinhealth=100

Answer 2

def goblin():
    ............
    health=health-goblinatk
    ............

看看这个函数定义。您的函数不知道health是什么，因此它不允许您从health下标内容。

因此，某种程度上，函数必须识别health是什么。两种最常见的方式：

第一种方式，将health声明为全局变量。现在可以在全球范围内识别health。但这不是最好的方法，因为处理全局变量很难且容易出错，而且你已经处理了太多的全局变量。所以，我不会推荐它。我宁愿建议你用方法2替换所有全局变量。要理解我为什么这么说，Read This Question
第二种方式，推荐的方法是将health变量作为函数的参数传递，最后从函数返回。

像这样：

def goblin(health):
    ............
    health=health-goblinatk
    ............
    return health

如果您已经归还了某些东西，请不要担心。使用python，您可以将多个变量作为元组返回。

return statement：

return a,b,c

调用声明：

a,b,c = func()

希望这有帮助:)

在赋值Python之前的变量refrenced

2 个答案: