熄灯

Question

我真的可以帮助理解我在2d列表理解方面出错了。我已经花了几个小时和更精细的点，为什么它没有工作继续逃避我。

以下代码是一个非常基本的Lights out game，它接受​​输入

runGenerations2d([0,1,1,0],[1,0,1,0],[1,0,1,0])

设置游戏板N x N

单击

需要更改单击框的值。

我相信问题是     setNewElement

正在使用x，y数据，其余的函数都不知道如何处理传递的值

import time # provides time.sleep(0.5)
from csplot import choice
from random import * # provides choice( [0,1] ), etc.
import sys  # larger recursive stack
sys.setrecursionlimit(100000) # 100,000 deep


def runGenerations2d(L , x = 0,y=0):
    show(L)
    print( L )           # display the list, L
    time.sleep(.1)      # pause a bit
    newL = evolve2d( L )   # evolve L into newL
    print(newL)
    if min(L) == 1:
        #I like read outs to be explained so I added an extra print command.
        if x<=1: # Takes into account the possibility of a 1 click completition.
            print ('BaseCase Reached!... it took %i click to complete' % (x))
            print (x)
            done()#removes the need to input done() into the shell
        else:
            print ('BaseCase Reached!... it took %i clicks to complete' % (x))
            print (x)
            done()#removes the need to input done() into the shell
        return   
    x = x+1 # add 1 to x before every recusion
    runGenerations2d( newL , x,y )  # recurse

def evolve2d( L ):
    N = len(L)  # N now holds the size of the list L
    x,y = sqinput2()  # Get 2D mouse input from the user
    print(x,y) #confirm the location clicked
    return [ setNewElement2d( L, i,x,y ) for i in range(N) ]


 def setNewElement2d( L, i, x=0,y=0 ):
    if i == (x,y): # if it's the user's chosen column,
        if L[i]==1: # if the cell is already one
            return L[i]-1 # make it 0
        else: # else the cell must be 0
            return L[i]+1 # so make it 1

点击后的错误

[None, None, None, None]
[None, None, None, None]
The data does not seem 2d.
Try using sqinput instead.

Answer 1

setNewElement2d返回一个数字，但调用代码需要两个数字。

这一行

return [ setNewElement2d( L, i,x,y ) for i in range(N) ]

将i设置为0，然后设置为1，然后设置为2，...则设置为N-1。这些是单个数字。

然后将这一行中的单个数字与两个数字进行比较：

if i == (x,y):

你似乎假设我是一对x，y对，但它不是。

以下是如何为3x3网格创建每个x-y对：

# Makes (0,0),(0,1)...(2,2)
[(x,y) for x in range(3) for y in range(3)]

我认为这段代码更接近你想要的，仍然需要改变：

def evolve2d( L ):
    N = len(L)
    x,y = sqinput2()
    print(x,y)
    return [setNewElement2d(L, xx, yy, x, y) for xx in range(N) for yy in range(N)]


 def setNewElement2d( L, xx, yy, x=0,y=0 ):
    if (xx,yy) == (x,y): # if it's the user's chosen row and column
        # If it's already 1 return 0 else return 1
        return 0 if L[xx][yy]==1 else 1