当我尝试从矢量中删除一个元素时,我得到一个超出范围矢量的错误下标
std :: vector用户;在我的.hh
void Server::read_client(int socket)
{
int ret;
int size;
char buff[255];
std::string data = "Hello, world!";
size = 255;
ret = recv(socket, buff, size, 0);
if (ret == 0 || ret == SOCKET_ERROR)
{
std::cout << "Client [" << socket << "] disconnected." << std::endl;
for (int i = 0; i < this->users.size();)
{
if (this->users[i]->getId() == socket)
{
std::vector<User *>::iterator iter;
/*for (iter = this->users.begin(); iter != this->users.end();)
{
if ((*iter)->getId() == socket)
{
delete *iter;
closesocket(socket);
this->users.erase(iter); // crash here
return;
}
else
iter++;
}*/
closesocket(socket);
delete this->users[i];
this->users.erase(this->users.begin() + i); // crash here
return;
}
else
i++;
}
return;
}
}
我不知道为什么它会崩溃...即使我做了users.erase(users.begin());它不起作用,我得到同样的错误
答案 0 :(得分:1)
没有必要编写这么多代码,因为STL已经为您提供了所需的一切。
首先,您可以使用std::vector<std::unique_ptr<User>>
而忘记delete this->users[i]
。然后你可以使用std::find_if
来做脏工作:
std::vector<std::unique_ptr<User>> users;
int socket = ...;
auto it = std::find_if(users.begin(), users.end(), [socket](const std::unique_ptr<User>& user) { return user->getId() == socket; });
users.erase(it);