Question

我有一个MySql表，我想从中获取一个用户的电子邮件，其中给出了用户ID以指出信息。我想接收这封电子邮件，将其存储在一个变量中，然后用它给脚本中的某个人发送电子邮件。

到目前为止，我的代码仍未显示：

<

?php

$appid = $_POST["appid"];
$option1 = $_POST['radio'];

$servername = "localhost";
$username = "mcxjb";
$password = "password";
$dbname = "members1";

// Create connection
$conn = mysqli_connect($servername, $username, $password, $dbname);
// Check connection
if (!$conn) {
    die("Connection failed: " . mysqli_connect_error());
}

$sql = "UPDATE users SET user_level='$option1' WHERE userid=$appid";

if (mysqli_query($conn, $sql)) {
    echo "Success!";
} else {
    echo "Error " . mysqli_error($conn);
}


$emailsql = "SELECT email_address FROM users WHERE userid=$appid";

$query = mysql_query($emailsql);


mysqli_close($conn);



?>

该脚本允许用户批准或拒绝某个人申请。然后，它会将用户级别更新为已批准或已拒绝。然后我想通过使用他们给出的用户ID来提取他们的电子邮件，然后从SQL表中获取它来给用户发送电子邮件！

谢谢，标记

Answer 1

while ($row = mysqli_fetch_array($query))
        {    

          //access Email using $row['email_address']
            // use PHP mail function here

        }

Answer 2

对于您的更新查询，您需要更改此内容：

if(mysqli_query($conn, $sql))..

惠特：

if(mysqli_query($sql))...

要访问select查询的结果，您需要这样做：

while ($row = mysqli_fetch_array($query))
        {    

          //access Email using $row['email_address']
            // use PHP mail function here

        }

所以代码将是：

<?php

$appid = $_POST["appid"];
$option1 = $_POST['radio'];

$servername = "localhost";
$username = "mcxjb";
$password = "password";
$dbname = "members1";

// Create connection
$conn = mysqli_connect($servername, $username, $password, $dbname);
// Check connection
if (!$conn) {
    die("Connection failed: " . mysqli_connect_error());
}

$sql = "UPDATE users SET user_level='$option1' WHERE userid=$appid";

if (mysqli_query($conn, $sql)) {
    echo "Success!";
} else {
    echo "Error " . mysqli_error($conn);
}


$emailsql = "SELECT email_address FROM users WHERE userid=$appid";

$query = mysqli_query($conn, $emailsql);

while ($row = mysqli_fetch_array($query))
            {    

              //access Email using $row['email_address']
                // use PHP mail function here

            }

mysqli_close($conn);



?>

从MySql表中选择信息，然后将其存储到变量

2 个答案: