Question

此代码应该说＆＃34;请输入新密码＆＃34;如果您从我创建的列表中输入一个公共密码，但它没有，它只是说＆＃34;密码接受＆＃34;不应该这样。有人可以帮我吗？这是代码本身：

### Asks user for their name and password ###

print "Hello, what is your name?"

### Stores name in variable myName ###

myName = raw_input()

print "Nice to meet you "+myName+", please enter a password to continue."

common_passwords = [ '123456', 'password', '12345', '12345678', 'qwerty',
                     '1234567890', 'baseball', 'dragon', 'football', '1234567',
                     'monkey', 'letmein', 'abc123', '111111', 'mustang', 'access',
                     'shadow', 'master', 'michael', 'superman', '696969', '123123',
                     'batman', 'trustno1']

while True:
    password = raw_input()
    if len(password) < 8:
        print "Password is less than 8 characters."
        print "Your password has to be 8 characters or more."
        continue
    found = False
    for cpass in common_passwords:
        if cpass == password:
            print "You have selected a common password"
            print "Please choose a new password"
            found = True
            break
        if not found:
            print "Password Accepted"
            break

Answer 1

你想做的可能是：

for cpass in common_passwords:
        if cpass == password:
            print "You have selected a common password"
            print "Please choose a new password"
            found = True
            break  
if not found:
        print "Password Accepted"

因为您要检查输入的密码是否在common_password中找到，如果在之后 ，则密码正常。

此外，您只需使用以下方法检查是否存在密码：

If password in common_passwords: print "You have selected a common password" print "Please choose a new password" else : print "Password Accepted"

Answer 2

尝试if password in common_passwords，它将一次性测试所有常用密码。你当前的错误是当你遍历每一个时，如果第一个中的元素不匹配，那么它将接受它。

坚持我已经制作的代码

2 个答案: