Question

我有问题。我根据申请人的考试成绩制作排名系统。这是代码：

$testScore = "SELECT Overall_Score, First_Name
                      FROM applicant_details, person, person_details
                      where person.ID_No like person_details.ID_No and Position_Applied = 'Work137' and Person_Type = 'Applicant' and applicant_details.ID_No like person.ID_No";

$result = mysql_query($testScore);

$rank = 0;
$lastScore = false;
$rows = 0;

while( $row = mysql_fetch_array( $result ) ){               

       $name = $row['First_Name'];
       $overall = $row['Overall_Score'];
       $rows++;

       if( $lastScore != $overall){
           $lastScore = $overall;
           $rank = $rows;
        }
        echo"Name:$name rank:$rank score: $overall </br>";
}

此代码的输出是第一个要查询的人是数字1.示例输出：

姓名：Utaha等级：1分：85

姓名：Rikka等级：2分：90

我想要一个输出：

姓名：Utaha等级：2分：85

姓名：Rikka排名1得分：90

Answer 1

只需使用ORDER BY [列名进行排序] [DESC / ASC]按值排序......

SELECT Overall_Score, First_Name
                  FROM applicant_details, person, person_details
                  where person.ID_No like person_details.ID_No and Position_Applied = 'Work137' and Person_Type = 'Applicant' and applicant_details.ID_No like person.ID_No ORDER BY Overall_Score DESC

如果你想保留订单，那么应该使用mysql_num_rows（）来获得答案总数，并使用该数字对它们进行排名：

$rows = mysql_num_rows($result);
while( $row = mysql_fetch_array( $result ) ){               

   $name = $row['First_Name'];
   $overall = $row['Overall_Score'];

   if( $lastScore != $overall){
       $lastScore = $overall;
       $rank = $rows;
    }
    echo"Name:$name rank:$rank score: $overall </br>";
   $rows--;

}

Answer 2

您的查询中需要ORDER BY子句：

$testScore = "SELECT Overall_Score, First_Name
              FROM applicant_details, person, person_details
              WHERE person.ID_No like person_details.ID_No
              AND Position_Applied = 'Work137'
              AND Person_Type = 'Applicant'
              AND applicant_details.ID_No like person.ID_No
              ORDER BY Overall_Score DESC
";

正如Gordon Linoff所暗示的那样，您可以使用正确的JOIN语法来改进此查询：

$testScore = "SELECT Overall_Score, First_Name
              FROM applicant_details
              JOIN person ON applicant_details.ID_No like person.ID_No
              JOIN person_details ON person.ID_No like person_details.ID_No
              WHERE Position_Applied = 'Work137'
              AND Person_Type = 'Applicant'
              ORDER BY Overall_Score DESC
";

使用while循环对PHP MYSQL进行排名

2 个答案: