Question

我注意到使用（offset, fetch）和rownumber时的不同行为。

当我使用行号时，它会返回我期望的结果。

所以我的续集查询如下所示：

 ClanModel.findAll({
    order: [["Wins", "DESC"]],
    offset: page * 5,
    limit: 5
 })

从第一行开始的SQL查询

SELECT 
    [clid] AS [ClanId], [Name], [Wins], [Losses], 
    [totalPoint] AS [TotalPoints] 
FROM 
    [Clan] AS [Clan] 
ORDER BY 
    [Clan].[Wins] DESC 
    OFFSET 0 ROWS FETCH NEXT 5 ROWS ONLY;

结果：

[ { Name: 'Test6'},
  { Name: 'Test5'},
  { Name: 'Test4'},
  { Name: 'Test3'},
  { Name: 'Test2'} ]

第5个结果后的SQL查询：

SELECT 
    [clid] AS [ClanId], [Name], [Wins], [Losses],
    [totalPoint] AS [TotalPoints] 
FROM 
    [Clan] AS [Clan] 
ORDER BY 
    [Clan].[Wins] DESC 
    OFFSET 5 ROWS FETCH NEXT 5 ROWS ONLY;

结果：

[ { Name: 'Test5'},
  { Name: 'Test4'},
  { Name: 'Test3'},
  { Name: 'Test2'},
  { Name: 'Test1'} ]

行号查询：

 SELECT 
     [Name], [Wins], [Losses], [TotalPoints] AS [TotalPoints]
 FROM 
     (SELECT
          [clid] AS [ClanId], [Name], [Wins], [Losses],
          [totalPoint] AS [TotalPoints], 
          ROW_NUMBER() OVER (ORDER BY [Wins]) AS RowNum
      FROM 
          [Clan]) as Clan
 WHERE 
     Clan.RowNum BETWEEN 5 AND 10

返回我期望的结果：

Test5
Test6
Test7
Test8
Test9
Test10

我的数据库记录：

Test1
Test2
Test3
Test4
Test5
Test6
Test7
Test8
Test9
Test10

我想使用我的sequelize模型来获取我的数据，而不是使用普通的SQL查询。但我找不到在续集中使用行号的方法。

有没有办法继续使用sequelize来获取我的数据？

Answer 1

您没有显示完整的数据。所以，这是一个猜测：你在wins列中有联系。 order by的排序不稳定，甚至不一致，这意味着关系可以按任何顺序返回。所以，通过包含名称来解决这个问题：

SELECT [clid] AS [ClanId], [Name], [Wins], [Losses], [totalPoint] AS [TotalPoints]
FROM [Clan] AS [Clan]
ORDER BY [Clan].[Wins] DESC, Clan.Name
OFFSET 5 ROWS FETCH NEXT 5 ROWS ONLY;

假设Name是唯一的，这将使排序保持一致。如果这在SQL中有效，那么它应该很容易在sequelize中实现。

Sequelize使用ROW_NUMBER（）而不是OFFSET和FETCH

1 个答案: