我有这个var_dump结果
'children' =>
array (size=2)
0 => string 'children on row 1' (length=17)
1 => string 'children on row 2' (length=17)
'type_of_delivery' =>
array (size=2)
0 => string 'type of delivery on row 1' (length=25)
1 => string 'type of delivery on row 2' (length=25)
'date' =>
array (size=2)
0 => string 'Oct 11, 2015' (length=12)
1 => string 'Oct 11, 2015' (length=12)
来自我的输入
<table>
<thead>
<tr>
<th>Children</th>
<th>Type of Delivery</th>
<th>Date</th>
<tr>
<thead>
<tbody>
<tr>
<td><input type="text" name="children[]" /></td>
<td><input type="text" name="type_of_delivery[]" /></td>
<td><input type="text" name="date[]" /></td>
</tr>
<tr>
<td><input type="text" name="children[]" /></td>
<td><input type="text" name="type_of_delivery[]" /></td>
<td><input type="text" name="date[]" /></td>
</tr>
</tbody>
</table>
我有一个专栏&#39;孩子&#39;&#39; type_of_delivery&#39;&#39; date&#39;对于那些请求数据。我希望像每组一样保存它,例如子类的数组0 + type_of_delivery的数组0 +数组0的日期等等。
假设我已成功保存这些数据,它应该是这样的。
--------------------------------------------------------------
children | type of delivery | date
--------------------------------------------------------------
children on row 1 | type of delivery on row 1 | Oct 11, 2015
children on row 2 | type of delivery on row 2 | Oct 11, 2015
任何想法,线索,帮助如何取悦它?
答案 0 :(得分:-1)
如果您的阵列保持相同的格式,您可以执行以下操作: -
$children = $arr['children'];
for (i=0; i < count($children); i++)
{
$update = [
'children' => $children[$i],
'type_of_delivery' => $arr['type_of_delivery'][$i],
'date' => $arr['date'][$i],
];
Your\Model\To\Insert::create($update);
}
这仅适用于children
,delivery
和date
之间的结果相同的情况。 var nonparent = $('.notParent');
var position = nonparent.offset();
$('.child1').offset({
top: position.top,
left: position.left
});