Question

我写了一个汇总代码来总结五个数字。然后将最终值存储在存储器中。

dtseg    segment
data     dw       27345,28521,29533,30105,32375
sum      dw       ?  
MSG1     DB "The sum is : $"  
dtseg    ends
;---------------------
cdseg    segment
main     proc     far
     assume   cs:cdseg,ds:dtseg,ss:stseg
     mov      ax,dtseg
     mov      ds,ax
     clc                       ; clear the carry
     mov      si,offset data   ; first location of data
     mov      cx,04            ; setting the counter
     mov      ax,0             ; clear ax
     mov      bx,ax            ; clear bx
back:add      ax,[si]          ; the first round: 0+27345
     adc      bx,0             ; if there is a carry, add that to bx
     inc      si               ; two inc because traversing words
     inc      si
     dec      cx               ; count down
     jnz      back             ; do that for other numbers
     mov      sum,ax           ; the final value
     mov      sum+2,bx         ; the carries are stored in bx

     lea      dx,MSG1          ; trying to display the result
     mov      ah,09h
     int      21h  
     mov      ah, 4cH          ; return to DOS
     int      21h
main     endp
cdseg    ends  
         end      main

我按照此topic进行了示例，但它在emu8086中不起作用

Answer 1

This example向您展示如何将DIV中的WORD值转换为字符串并输出。您想要将DWORD值转换为字符串。在您的情况下，您可以使用DX在寄存器DX：AX中划分DWORD的优势。在示例xor dx, dx中设置为0，因此第一个想法是删除行DX。但是你第一次需要DIV，那么你必须清除它，因为它保留了dtseg segment data dw 27345,28521,29533,30105,32375 ; Sum: 147879 sum dw ?, ? ; two WORD = one DWORD MSG1 DB "The sum is : $" DECIMAL db "0000000000$" ; space for the result dtseg ends ;--------------------- cdseg segment main proc far assume cs:cdseg,ds:dtseg,ss:stseg mov ax,dtseg mov ds,ax clc ; clear the carry mov si,offset data ; first location of data mov cx,5 ; setting the counter mov ax,0 ; clear ax mov bx,ax ; clear bx back:add ax,[si] ; the first round: 0+27345 adc bx,0 ; if there is a carry, add that to bx inc si ; two inc because traversing words inc si dec cx ; count down jnz back ; do that for other numbers mov sum,ax ; the final value mov sum+2,bx ; the carries are stored in bx call mem_to_dec lea dx,MSG1 ; trying to display the result mov ah,09h int 21h lea dx,DECIMAL ; trying to display the result mov ah,09h int 21h mov ah, 4cH ; return to DOS int 21h main endp mem_to_dec proc mov ax, [sum] mov dx, [sum+2] mov bx, 10 ; divisor xor cx, cx ; CX=0 (number of digits) @First_Loop: div bx ; DX:AX / BX = AX remainder: DX push dx ; LIFO inc cx ; increment number of digits xor dx, dx ; Clear DX for the next DIV test ax, ax ; AX = 0? jnz @First_Loop ; no: once more mov di, OFFSET DECIMAL ; target string DECIMAL @Second_Loop: pop ax ; get back pushed digit or ax, 00110000b ; to ASCII mov byte ptr [di], al ; save AL inc di ; DI points to next character in string DECIMAL loop @Second_Loop ; until there are no digits left mov byte ptr [di], '$' ; End-of-string delimiter for INT 21 / FN 09h ret mem_to_dec endp cdseg ends end main之后的余数。诀窍是在div之前执行之后的清除。因此它将首次使用，并在每次重复时清除。

DIV

如果结果不适合AX注册，library(igraph) g <- ba.game(10) # sample graph V(g)$label <- LETTERS[1:10] # set vertex labels to A-J E(g)$foo <- sample(1:5, 10, T) # set custom edge label... names(edge_attr(g))[which(names(edge_attr(g)) == "foo")] <- "weight" # ... and rename it to weight write_graph(g, tf <- tempfile(fileext = ".graphml"), "graphml") # export graph system(paste('"C:\\Program Files (x86)\\Gephi-0.8.2\\bin\\gephi.exe"', tf), wait = FALSE) # adjust path here会出现问题。然后你得到一个溢出错误。

在装配中在屏幕上打印内存值

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