类,实例和对象的问题

时间:2015-10-10 22:40:45

标签: php mysql class object

我对PHP很新;但是我觉得我对它有很好的把握,但是我有一个问题,理解为什么我无法访问第二版连接到DB类的连接。

我在配置脚本中全局连接到第一个。

$db = new db(array('login info'));

我使用以下内容在我的控制器中访问它。

public $db;
public function __construct(){
    $this->db = $GLOBALS['db'];
}

然后在我的控制器中我有一个函数,我在其中创建一个新的实例来连接到另一个DB。

$ordersDB = new db(array('login info'));

现在我想使用

之类的东西单独访问每个数据库
$this->db->select("SELECT * FROM ada Yada 

$ordersDB->select("SELECT * FROM Yada Yada

然而,两者仍在访问第一个数据库。我知道这是因为我在执行第二个时遇到一个表不存在错误,它告诉我它的查询是什么db。然而,它们的var_export显示它们实际上是不同的!我完全误解了课程是如何工作的,或者我一次只能打开一个数据库?谢谢你的帮助。

编辑:这是你要找的吗?

$db = new db(array(connect info));
$controller = new controller();
$controller->connectToSecondDB();

class db {

    public $dbHost;
    public $dbUser;
    public $dbName;
    public $dbPassword;

    public function __construct() {
       $arguments = func_get_args();

       if(!empty($arguments)){
          foreach($arguments[0] as $key => $property){
            if(property_exists($this, $key)){
                $this->{$key} = $property;
            }
           }
       }
    }

  public function connect() {            
        if(!isset(self::$connection)) {       
            self::$connection = new mysqli($this->dbHost, $this->dbUser, $this->dbPassword, $this->dbName);
        }
}

class controller {
   public $db;
   public function __construct(){
      $this->db = $GLOBALS['db'];
   }

   public function connectToSecondDB(){
      $ordersDB = new db(array(connect info));
      $ordersDB->select("SELECT * FROM `customer` WHERE email = 'email@address.com' LIMIT 1")
      $this->db->query("SQL");
   }
}

编辑选择查询功能

private function _sel($table, $where="", $order_by="", $limit="", $group_by="",$database = NULL){
        if($database === NULL) {  $database = $this->db; }
        if($limit == 1){ $single = true; }else{ $single = false; }

        //if( is_array($where) ){ $this->_buildWhere(); }
        $where = (strlen($where) > 0) ? "WHERE $where " : $where;       
        $group_by = (strlen($group_by) > 0) ? "GROUP BY $group_by " : $group_by;        
        $order_by = (strlen($order_by) > 0) ? "ORDER BY $order_by " : $order_by;        
        $limit = (strlen($limit) > 0) ? "LIMIT $limit " : $limit ;

        $sql = "SELECT * 
                FROM `$table` 
                $where 
                $group_by 
                $order_by 
                $limit";
        // Debug

//if(INCLUDE_CHECK){ echo "<HR>".$sql."<HR>";   }
        $results = $database->select($sql); 
        if($single && count($results) > 0 ){
            return($results[0]);
        }else{
            return($results);
        }
    }

1 个答案:

答案 0 :(得分:1)

解决方案是重用$ controller对象。添加query方法。然后,您可以独立于连接方法运行查询,以便可以重用控制器对象

您需要在整个过程中的每个步骤进行错误检查。

请注意,我删除了$this->db->query("SQL");,因为我不确定它究竟是做了什么。答案中的概念应该让您开始重新设计您的课程。

<强>更新 根据评论,我从超级全局更改$ db并将其传递给控制器​​对象。

$db = new db(array(connect info));
// try passing the $db object so it does not need to be a super global
$controller = new controller($db);
// You can keep your $controller object as a global - I use a session variable for this to reuse it between pages.
$controller->connectToSecondDB();
// run the query separate from the connection so the controller object can be reused
$result = $controller->ordersQuery("SELECT * FROM `customer` WHERE email = 'email@address.com' LIMIT 1")


class db {

    public $dbHost;
    public $dbUser;
    public $dbName;
    public $dbPassword;
    public $connection;

    public function __construct() {
       $arguments = func_get_args();

       if(!empty($arguments)){
          foreach($arguments[0] as $key => $property){
            if(property_exists($this, $key)){
                $this->{$key} = $property;
            }
           }
       }
    }

  public function connect() {            
        if(!isset($this->$connection)) {       
            $this->connection = new mysqli($this->dbHost, $this->dbUser, $this->dbPassword, $this->dbName);
        }
}

class controller() {
   public $db;
   public $ordersDB;    // ADD THIS

   public function __construct($db2){
      $this->db = $db2;
   }

   public function connectToSecondDB(connect info){
      $ordersDB = new db(array(connect info));
   }

   public function ordersQuery($sql){
      $this->ordersDB->query($sql)
      // Fetch and return you result set here
   }

}