我想在tableviewcontroller中显示搜索到的核心数据结果。我知道如何在tableview中显示核心数据,但我希望在tableviewcontroller中显示特定数据。
例如,当用户从uipickerview中选择特定城市时,则根据特定城市从tableviewcontroller中显示核心数据的结果。
下面列出了一些代码。
导入UIKit 导入CoreData
类MenuhospitalTableViewController:UITableViewController {
private var hospitalcoredata: [Hospitalcoredata] = []
var fetchResultController:NSFetchedResultsController!
override func viewDidLoad() {
super.viewDidLoad()
Load menu items from database
if let managedObjectContextt = (UIApplication.sharedApplication().delegate as! AppDelegate).managedObjectContextt {
let fetchRequest = NSFetchRequest(entityName: "Hospitalcoredata")
var e: NSError?
hospitalcoredata = managedObjectContextt.executeFetchRequest(fetchRequest, error: &e) as! [Hospitalcoredata]
if e != nil {
println("Failed to retrieve record: \(e!.localizedDescription)")
}
}
// Make the cell self size
self.tableView.estimatedRowHeight = 66.0
self.tableView.rowHeight = UITableViewAutomaticDimension
self.tableView.layoutIfNeeded()
}
override func didReceiveMemoryWarning() {
super.didReceiveMemoryWarning()
// Dispose of any resources that can be recreated.
}
// MARK: - Table view data source
override func numberOfSectionsInTableView(tableView: UITableView) -> Int {
// Return the number of sections.
return 1
}
override func tableView(tableView: UITableView, numberOfRowsInSection section: Int) -> Int {
// Return the number of rows in the section.
return hospitalcoredata.count
}
override func tableView(tableView: UITableView, cellForRowAtIndexPath indexPath: NSIndexPath) -> UITableViewCell {
let cell = tableView.dequeueReusableCellWithIdentifier("Cell", forIndexPath: indexPath) as! MenuhospitalTableViewCell
// Configure the cell...
cell.nameLabel.text = hospitalcoredata[indexPath.row].namee
cell.contactnoLabel.text = hospitalcoredata[indexPath.row].contactnoo
// cell.priceLabel.text = "$\(menuItems[indexPath.row].price as! Double)"
return cell
}
/*
// MARK: - Navigation
// In a storyboard-based application, you will often want to do a little preparation before navigation
override func prepareForSegue(segue: UIStoryboardSegue, sender: AnyObject?) {
// Get the new view controller using [segue destinationViewController].
// Pass the selected object to the new view controller.
}
*/}
以及从城市查找数据的代码如下所示。
let entityDescription =
NSEntityDescription.entityForName("Register",
inManagedObjectContext: managedObjectContext!)
let request = NSFetchRequest()
request.entity = entityDescription
let pred = NSPredicate(format: "(name = %@)", name.text)
request.predicate = pred
var error: NSError?
var objects = managedObjectContext?.executeFetchRequest(request,
error: &error)
if let results = objects {
if results.count > 0 {
let match = results[0] as! NSManagedObject
name.text = match.valueForKey("name") as! String
contactno.text = match.valueForKey("contactno") as! String
altno.text = match.valueForKey("altno") as! String
emailid.text = match.valueForKey("emailid") as! String
textf.text = match.valueForKey("bloodgroup") as! String
textff.text = match.valueForKey("city") as! String
status.text = "Matches found: \(results.count)"
} else {
status.text = "No Match"
}
}
}
我想混淆这两个代码并相应地显示核心数据结果" city"选择。
答案 0 :(得分:1)
您应该使用NSFetchedResultsController
填充表格视图。在更新表视图之前,将动态谓词添加到其获取请求和performFetch
。
答案 1 :(得分:0)
经过我的项目指南(教授chirag pandya)的大量尝试和帮助后,
答案:
在第一个视图控制器中使用preparesegue方法, 给推塞赛的名字, 使用segue名称, 在第二个视图控制器中创建谓词并使用第一个viewcontroller。 对于搜索和排序非常有用
代码: 1)IN(firstviewcontroller)
override func prepareForSegue(segue: UIStoryboardSegue, sender: AnyObject?) {
if(segue.identifier=="segueTest"){
var svc = segue.destinationViewController as! MenuhospitalTableViewController
svc.toPass = textff.text
}
}
2)IN(secondviewcontroller)
let pred = NSPredicate(format: "(city = %@)", toPass)
fetchRequest.predicate = pred