Question

我是新来的，我希望不要犯任何错误！

我正在尝试使这个简单的代码工作，我在Python 3.4 32位测试它并且它工作但我需要在Python 3.5.0 64位上使用它但我得到这个错误，我不知道如何修复。

import pythoncom, pyHook

def OnKeyboardEvent(event):
    key=chr(event.Ascii)
    print(key)

hm = pyHook.HookManager()
hm.KeyDown = OnKeyboardEvent
hm.HookKeyboard()
pythoncom.PumpMessages()

我按下了屏幕上的按键，然后我收到了这个错误：

During handling of the above exception, another exception occurred:
Traceback (most recent call last):
File "C:\Python 3.5\lib\site-packages\pyHook\HookManager.py", line 348, in KeyboardSwitch
event = KeyboardEvent(msg, vk_code, scan_code, ascii, flags, time, hwnd, win_name)
File "C:\Python 3.5\lib\site-packages\pyHook\HookManager.py", line 208, in __init__
HookEvent.__init__(self, msg, time, hwnd, window_name)
SystemError: PyEval_EvalFrameEx returned a result with an error set
TypeError: an integer is required (got type NoneType)

我真的不知道该怎么做！

Answer 1

您的函数需要返回一个整数值：

def OnKeyboardEvent(event):
    key=chr(event.Ascii)
    print(key)
    return 0

Python 3.5 HookManager SystemError：PyEval_EvalFrameEx

1 个答案: