Question

我正在尝试使用linkedin API为请求令牌交换auth代码。但是我试着总是收到错误：

{[“error_description”] =＆gt; string（107）“缺少必需的参数，包含无效参数值，参数不止一次。： client_secret“[”error“] =＆gt; string（15）”invalid_request“}

我的代码如下：

 public function authorization($authCode)
    {
        //define enviroment and path
        $host = "https://www.linkedin.com/uas/oauth2/accessToken";

        // Generate urlencode data
        $data_string = 'grant_type=authorization_code';
        $data_string .= '&code='.$authCode;
        $data_string .= '&redirect_uri='.redirectUrl;
        $data_string .= '&client_id='.publicKey;
        $data_string .= '&client_secret'.secretKey;
        var_dump($data_string);


        // set up the curl resource
        $ch = curl_init();
        curl_setopt($ch, CURLOPT_URL, $host);
        curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
        curl_setopt($ch, CURLOPT_CUSTOMREQUEST, "POST");
        curl_setopt($ch, CURLOPT_POST, true);
        curl_setopt($ch, CURLOPT_POSTFIELDS, $data_string);
        curl_setopt($ch, CURLOPT_HEADER, false);
        curl_setopt($ch, CURLOPT_VERBOSE, true);
        curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
        curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false);
        curl_setopt($ch, CURLOPT_HTTPHEADER, array(
            'Content-Type: application/x-www-form-urlencoded',
        ));

        // execute the request
        $output = curl_exec($ch);

        //echo($output) . PHP_EOL;
        $output = json_decode($output);
        var_dump($output);

        echo $output->access_token;

        // close curl resource to free up system resources
        curl_close($ch);
    }

简单的函数调用就像：

if(!empty($_GET['code']))
{
    $state = $_GET['state'];
    $authCode = $_GET['code'];
    $LinkedIn->authorization($authCode);
}

我尝试通过postman使用我的数据进行此请求，并且我成功获得了Access令牌，所以我在这里有一些我看不到的错误。

有谁能告诉我我做错了什么？感谢

Answer 1

我认为你需要等同于＆＃39;在client_secret之后签名

<script>
    var currentx = 0,
        viewport = 1920;
    $(window).keydown(function (e) {
        var btnright = (+currentx) + (+viewport),
            btnleft = (+currentx) - (-viewport);
        if ( e.which == 37 ) {
            window.scrollTo(btnleft, 0);
            currentx = (+currentx) - (-viewport);
        } else if ( e.which == 39 ) {
            window.scrollTo(btnright, 0);
            currentx = (+currentx) + (+viewport);
        }
    });
</script>

Linkedin - 请求令牌的交换授权码

1 个答案: