Question

我在我的字符串文件中创建了一个数组（在values文件夹中）。现在我想用它来选择旋转器，使用开关盒。类似的东西：

ArrayAdapter adapter = new ArrayAdapter(this,android.R.layout.simple_dropdown_item_1line,workers);
spinner.setAdapter(adapter);
spinner.setOnItemSelectedListener(this);

public void addUser(View view) {

            switch (Arrays.toString(workers)){

                case workers[0]:        //this option isn't compiling
                    Waiter waiter = new Waiter();

                    waiter.setName(editName.getText().toString());
                    waiter.setLast(editLast.getText().toString());
                    waiter.setPass(editPass.getText().toString());

                    name = editName.getText().toString();
                    last = editLast.getText().toString();
                    passId = Integer.parseInt(editPass.getText().toString());
               break;

               case workers[1]:
               break; 
}

依旧......

编辑：

现在尝试使用if语句，这个方法应该在按下按钮时添加新工作者，但在那之后当我按下按钮时没有任何反应：

public void addUser(View view) {

    if(Arrays.toString(workers).equals(workers[0])) {

        Waiter waiter = new Waiter();

        SQLiteDatabase usersDB = openOrCreateDatabase("USERES_DATABSE.sqlite", MODE_PRIVATE, null);
        usersDB.execSQL("CREATE TABLE IF NOT EXISTS users_table (name TEXT, last TEXT, pass INTEGER)");

        waiter.setName(editName.getText().toString());
        waiter.setLast(editLast.getText().toString());
        waiter.setPass(editPass.getText().toString());

        name = editName.getText().toString();
        last = editLast.getText().toString();
        passId = Integer.parseInt(editPass.getText().toString());


        if (editName.getText().toString().isEmpty() ||
                editLast.getText().toString().isEmpty() ||
                editPass.getText().toString().isEmpty()) {


            AlertDialog alertDialog = new AlertDialog.Builder(UserCreatingActivity.this).create();
            alertDialog.setTitle("Oops,");
            alertDialog.setMessage("You forgot to fill something");
            alertDialog.setButton("OK", new DialogInterface.OnClickListener() {

                @Override
                public void onClick(DialogInterface dialog, int which) {


                }
            });

            alertDialog.show();


        } else {

            usersDB.execSQL("INSERT INTO users_table VALUES('" + name + "','" + last + "','" + passId + "')");


            AlertDialog alertSucsess = new AlertDialog.Builder(UserCreatingActivity.this).create();
            alertSucsess.setTitle("Congrats,");
            alertSucsess.setMessage(name + " " + last + " Has been created");
            alertSucsess.setButton("OK", new DialogInterface.OnClickListener() {

                @Override
                public void onClick(DialogInterface dialog, int which) {

                    startActivity(new Intent(getApplicationContext(), MainActivity.class));

                }
            });

            alertSucsess.show();

        }

        usersDB.close();

//          ADDING SHIFT MANAGER

        } else if (Arrays.toString(workers).equals(workers[1])){

Answer 1

您无法在交换机中使用变量。改为if。

或者你可以改为案例0：，案例1：，案例2：因为它总是工人[]

Answer 2

case表达式必须是常量值。

如果预定义了workers的可能值，请将这些预定义和常量值用作case表达式。

Answer 3

正如大家提到的那样，无法使用带开关的阵列，因此您需要使用if 。你写条件的方式似乎不正确if(Arrays.toString(workers).equals(workers[0]))。经过问题然后根据微调器中的选择你必须添加用户...如果我错了，请纠正我。所以首先你需要找到微调器的值的解决方法1
创建一个实例String变量并按如下方式实现onItemSelected。

String workerSelected; //your code spinner.setOnItemSelectedListener(new OnItemSelectedListener() { @Override public void onItemSelected(AdapterView<?> arg0, View arg1, int position, long arg3) { workerSelected=worker[position] } @Override public void onNothingSelected(AdapterView<?> arg0) { // TODO Auto-generated method stub } });

或由于您已添加spinner.setOnItemSelectedListener(this);，因此只需直接覆盖方法，即代码足够

@Override public void onItemSelected(AdapterView<?> arg0, View arg1, int position, long arg3) { workerSelected=worker[position] }

然后在 addUser方法中，你可以将if条件作为

if(workerSelected.equals(worker[0])){ //your code }else if(workerSelected.equals(worker[1])){ //your code }

<强>溶液2
直接在 addUser方法
中
String workerSelected = spinner.getSelectedItem().toString(); if(workerSelected.equals(worker[0])){ //your code }else if(workerSelected.equals(worker[1])){ //your code }

无法使用数组用于切换案例

3 个答案: