我正在创建一个小应用程序,我可以使用内容提供商获取手机的联系人,并将其显示在列表视图中,如图所示。
我想选择列表视图的一行,并自动拨打该特定联系人的电话。我尝试了一些东西,但它们不起作用。有任何想法吗?这是我的代码。
public class MainActivity extends ListActivity implements AdapterView.OnItemClickListener{
ArrayAdapter<String> adapter;
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
ContentResolver cr = getContentResolver();
Cursor c = cr.query(ContactsContract.Contacts.CONTENT_URI,
new String[] {ContactsContract.Contacts.DISPLAY_NAME},
null, null, null);
List<String> contacts = new ArrayList<String>();
if (c.moveToFirst()) {
do {
contacts.add(c.getString(c.getColumnIndex(ContactsContract.Contacts.DISPLAY_NAME)));
} while (c.moveToNext());
}
adapter = new ArrayAdapter<String>(this, R.layout.activity_main, contacts);
setListAdapter(adapter);
}
@Override
public void onItemClick(AdapterView<?> parent, View view, int position, long id) {
//The answer should be inside here.
}
}
答案 0 :(得分:4)
首先,确保您已添加权限:
<uses-permission android:name="android.permission.READ_CONTACTS"/>
到您的AndroidManifest.xml文件,然后您可以循环访问您的手机通讯录:
Cursor cursor = getContentResolver().query(ContactsContract.Contacts.CONTENT_URI,null, null, null, null);
while (cursor.moveToNext()) {
String contactId = cursor.getString(cursor.getColumnIndex(
String hasPhone = cursor.getString(cursor.getColumnIndex(ContactsContract.Contacts.HAS_PHONE_NUMBER));
if (Boolean.parseBoolean(hasPhone)) {
// You know it has a number so now query it like this
Cursor phones = getContentResolver().query( ContactsContract.CommonDataKinds.Phone.CONTENT_URI, null, ContactsContract.CommonDataKinds.Phone.CONTACT_ID +" = "+ contactId, null, null);
while (phones.moveToNext()) {
String phoneNumber = phones.getString(phones.getColumnIndex( ContactsContract.CommonDataKinds.Phone.NUMBER));
}
phones.close();
}
Cursor emails = getContentResolver().query(ContactsContract.CommonDataKinds.Email.CONTENT_URI, null, ContactsContract.CommonDataKinds.Email.CONTACT_ID + " = " + contactId, null, null);
while (emails.moveToNext()) {
// This would allow you get several email addresses
String emailAddress = emails.getString(
emails.getColumnIndex(ContactsContract.CommonDataKinds.Email.DATA));
}
emails.close();
}
答案 1 :(得分:1)
尝试:
private void doMagicContacts() {
Cursor cursor = getContentResolver()
.query(ContactsContract.Contacts.CONTENT_URI,
null,
null,
null,
null);
if (cursor == null) {
return;
}
cursor.moveToFirst();
do {
String name = cursor.getString(
cursor.getColumnIndex(ContactsContract.Contacts.DISPLAY_NAME));
String id = cursor.getString(
cursor.getColumnIndex(ContactsContract.Contacts.NAME_RAW_CONTACT_ID));
Cursor phones = getContentResolver()
.query(ContactsContract.CommonDataKinds.Phone.CONTENT_URI,
null,
ContactsContract.CommonDataKinds.Phone.CONTACT_ID + " = " + id,
null,
null);
if (phones != null) {
while (phones.moveToNext()) {
String phoneNumber = phones.getString(
phones.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER));
Log.d(TAG, "doMagicContacts: " + name + " " + phoneNumber);
}
phones.close();
}
} while (cursor.moveToNext());
cursor.close();
}