Question

所以我的问题是没有正确递增...我试图使用int＆＃34; step＆＃34;每次运行此循环时为+ 1，但它没有做任何事情。这是为什么？此外，当我打印（步骤）它只加起来337.它不像我想象的那样完整的1000。我该如何正确地做到这一点？

lockers = []

step = 3

locker = 0

while len(lockers) <= 1000:
     lockers.append(1)

for i in range(0, len(lockers)):
     lockers[i] = 0

for i in range(0, len(lockers), 2):
     lockers[i] = 1

for i in range(0, len(lockers), step):
     if lockers[i] == 0:
          lockers [i] = 1
     else:
          lockers[i] = 0

     step += 1


print(lockers)

Answer 1

如果要在迭代时调整步长，可以拥有自己的范围对象：

class AdjustableRange(object):
    def __init__(self, start, stop, step):
        self.start = start
        self.stop = stop
        self.step = step
        self.value = None
    def __iter__(self):
        if self.value is None:
            self.value = start
        while self.value < self.stop:
            yield self.value
            self.value += self.step

这个（未经测试的）可用于迭代的

rg = AdjustableRange(0, len(lockers), step):
for i in rg:
    if lockers[i] == 0:
        lockers [i] = 1
    else:
        lockers[i] = 0
    rg.step += 1 # this influences the iteration

但是，正如已经说过的，有更好的方法来解决你的“真正的”问题。

增加for循环

1 个答案: