我有一张这样的表:
RowID | ProductDescription1
-----------------------------------------------------
1 | 0296620300-0296620399;
2 | 0296620400-0296620499;0296620500-0296620599;
3 | 0296620600-0296620699;0296620700-0296620799;
我想变成这样:
NewRowID | Start | End | SourceRowID
--------------------------------------------------
1 | 0296620300 | 0296620399 | 1
2 | 0296620400 | 0296620499 | 2
3 | 0296620500 | 0296620599 | 2
4 | 0296620600 | 0296620699 | 3
5 | 0296620700 | 0296620799 | 3
现在我有一个函数可以拆分返回表的东西:
ALTER FUNCTION [dbo].[ufn_stg_SplitString]
(
-- Add the parameters for the function here
@myString varchar(500),
@deliminator varchar(10)
)
RETURNS
@ReturnTable TABLE
(
-- Add the column definitions for the TABLE variable here
[id] [int] IDENTITY(1,1) NOT NULL,
[part] [varchar](50) NULL
)
AS
BEGIN
Declare @iSpaces int
Declare @part varchar(50)
--initialize spaces
Select @iSpaces = charindex(@deliminator,@myString,0)
While @iSpaces > 0
Begin
Select @part = substring(@myString,0,charindex(@deliminator,@myString,0))
Insert Into @ReturnTable(part)
Select @part
Select @myString = substring(@mystring,charindex(@deliminator,@myString,0)+ len(@deliminator),len(@myString) - charindex(' ',@myString,0))
Select @iSpaces = charindex(@deliminator,@myString,0)
end
If len(@myString) > 0
Insert Into @ReturnTable
Select @myString
RETURN
END
如果可能,我想避免使用光标。
感谢您的评论/意见。
答案 0 :(得分:2)
SQL 2005/2008
with prods as
(
select 1 as RowID, '0296620300-0296620399;' AS ProductDescription1 union all
select 2 as RowID, '0296620400-0296620499;0296620500-0296620599;' AS ProductDescription1 union all
select 3 as RowID, '0296620600-0296620699;0296620700-0296620799;' AS ProductDescription1
)
select
ROW_NUMBER() OVER(ORDER BY RowId) as NewRowID,
LEFT(Part,10) AS Start, /*Might need charindex if they are not always 10 characters*/
RIGHT(Part,10) AS [End],
RowId as SourceRowID from prods
cross apply [dbo].[ufn_stg_SplitString] (ProductDescription1,';') p
给出
NewRowID Start End SourceRowID
-------------------- ---------- ---------- -----------
1 0296620300 0296620399 1
2 0296620400 0296620499 2
3 0296620500 0296620599 2
4 0296620600 0296620699 3
5 0296620700 0296620799 3
答案 1 :(得分:2)
首先,此解决方案需要SQL Server 2005+。其次,在底部,我提供了一个不使用游标的备用Split功能。第三,这里的解决方案不依赖于指定长度的值,而是分隔符是一致的:
Select Row_Number() Over ( Order By Z.PairNum ) As ItemNum
, Min(Case When Z.PositionNum = 1 Then Z.Value End) As [Start]
, Min(Case When Z.PositionNum = 2 Then Z.Value End) As [End]
, Z.RowId As SourceRowId
From (
Select T2.RowId, S.Value, T2.PairNum
, Row_Number() Over ( Partition By T2.RowId, T2.PairNum Order By S.Value ) As PositionNum
From (
Select T.RowId, S.Value
, Row_Number() Over ( Order By S.Value ) As PairNum
From MyTable As T
Cross Apply dbo.Split( T.ProductDescription, ';' ) As S
) As T2
Cross Apply dbo.Split( T2.Value, '-' ) As S
) As Z
Group By Z.RowId, Z.PairNum
分割功能:
Create FUNCTION [dbo].[Split]
(
@DelimitedList nvarchar(max)
, @Delimiter nvarchar(2) = ','
)
RETURNS TABLE
AS
RETURN
(
With CorrectedList As
(
Select Case When Left(@DelimitedList, Len(@Delimiter)) <> @Delimiter Then @Delimiter Else '' End
+ @DelimitedList
+ Case When Right(@DelimitedList, Len(@Delimiter)) <> @Delimiter Then @Delimiter Else '' End
As List
, Len(@Delimiter) As DelimiterLen
)
, Numbers As
(
Select TOP (Len(@DelimitedList)) Row_Number() Over ( Order By c1.object_id ) As Value
From sys.objects As c1
Cross Join sys.columns As c2
)
Select CharIndex(@Delimiter, CL.list, N.Value) + CL.DelimiterLen As Position
, Substring (
CL.List
, CharIndex(@Delimiter, CL.list, N.Value) + CL.DelimiterLen
, CharIndex(@Delimiter, CL.list, N.Value + 1)
- ( CharIndex(@Delimiter, CL.list, N.Value) + CL.DelimiterLen )
) As Value
From CorrectedList As CL
Cross Join Numbers As N
Where N.Value < Len(CL.List)
And Substring(CL.List, N.Value, CL.DelimiterLen) = @Delimiter
)