Question

我写了一个程序，它读取字符的文本文件字符并计算通过的元音量。但是，如果出现一个符号，说“*”，我希望程序停止计算元音并开始计算非元音，显然从那一点开始继续。我写了一个不同的功能并输入以下内容：

if (kar == '*'){
        reversecounting(i);
        return 0;
}

其中reversecounting是计算非元音的int函数。我现在遇到的问题是，每当它执行此操作时，计算非元音的函数将从文件的开头开始。有没有办法让它从另一个函数停止的点开始继续？

我正在使用“get”函数从文件中读取。提前谢谢。

编辑：抱歉不包含相关代码，我现在已经添加了一些评论以使其易于理解

#include <iostream>
#include <fstream>
#include <cstdlib>

using namespace std;

int countnonvowels( int &k ); //prototype

int countvowels( int k ){ //start function to count vowels
ifstream input; //to open textfile
char kar;      // this is the character that will be read
int countvowels = 0; //local counter of vowels


input.open ("input.txt",ios::in); //opening the textfile


    kar = input.get ( ); //first obtain a character from the textfile
    while ( ! input.eof ( ) ) { //reads the file untile end of file
        kar = input.get ( ); //the next character in the file gets "read"

      if( kar == 'e' or kar == 'a' or kar == 'i' or kar == 'o' or kar == 'u' ){ //checks whether the character is a vowel
            countvowels++; //local counter goes up by one
            kar = input.get(); //take the next letter and print it
            cout << kar << " " << countvowels << endl;
            countvowels = 0; //value becomes zero again
      }//if
      if (kar == '*'){ //if the character is a "*", I want the non-vowels to be counted and the k-th non-vowel to be printed
            countnonvowels(k);
            return 0; //this function has to stop running
      }//if
    } // while

    input.close ( );




}//countvowels

int countnonvowels(int &k){//counts the non-vowels

ifstream input;
char kar;
int countnonvowels = 0;

input.open ("input.txt",ios::in); //open the file


    kar = input.get ( ); 
    while ( ! input.eof ( ) ) { //same while loop
        kar = input.get ( );

      if( kar != 'e' or kar != 'a' or kar != 'i' or kar != 'o' or kar != 'u' ){ //now i want the counter to roll if it is NOT a vowel
            countnonvowels++;
            cout << kar << endl;
      }
      if (kar == '*'){ //if a "*" appears, I want the vowels to be counted again
            countvowels(k);
            return 0;

      }//if
    } // while

input.close ( );


}//countnonvowels


int main ( ) {

countvowels(2);

    return 0;
} // main

这里的问题是我得到一个无限循环：文件被检查元音，它看到[星号]，开始计算文本开头的非元音，再次看到[星号]和从文本文件的开头开始计算元音......

星号（shift + 8）显然会使一切草书，我希望我的意思清楚哪一个。

Answer 1

这是一个简短的例子，因为你知道如何检查字母是否是元音。因为我怀疑这是一个家庭作业问题，所以我要修改它以便为你整个文件工作。

   void countLetters(const string& line)
    {
       int vowels, nonVowels;
       vowels = nonVowels = 0;
       bool countingVowels = true;
       for (int position = 0; position < line.length(); position++)
       {
          if (countingVowels && isVowel(line[position])
          {
             vowels++;
          }
          else if (!countingVowels && !isVowel(line[position]))
          {
             nonVowels++;
          } 
          else if (line[position] == '*')
          {
             countingVowels = !countingVowels;
          }
       }
       cout << vowels << " "<< nonVowels<<endl;
    }

从该点继续读取文件时结束函数

1 个答案: