Question

目标是：

第1行：A-L
  第2行：M-Z

编写一个程序，将学生的全名（最后一个）作为输入，并打印出学生应该在的行。第一个名字或姓氏将包含任何空格。输入中只有一个空格，它位于名字和姓氏之间。

我不知道如何让它读取字符A - L和M-Z.

import java.util.Scanner;

public class SeatingChart {
    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);

        char row1 = 'A' ,'L';
        char row2 = 'M' ,'Z';

        System.out.println(" Enter the student's last name: ");
        String name = in.next();

        char initial = name.charAt(0);

        if (initial = row1) {
            System.out.println(" This student can sit anywhere in row 1. ");
        }

        if (initial = row2) {
            System.out.println(" This student can sit anywhere in row 2. ");
        }

        in.close();
    }
}

这是我到目前为止所做的，但是代码对于声明字符A - L和字符M - Z是不正确的。如何解决这个问题以使其读取这些字符列表？

Answer 1

这样的事情应该有效（未经测试）：

if((initial >= 'A' && initial <= 'L') || (initial >= 'a' && initial <= 'l')){
    // If letter is between 'A' and 'L' or 'a' and 'l'
    System.out.println(" This student can sit anywhere in row 1. ");
} else if((initial >= 'M' && initial <= 'Z') || (initial >= 'm' && initial <= 'z')){
    // If letter is between 'M' and 'Z' or 'm' and 'z'
    System.out.println(" This student can sit anywhere in row 2. ");
}

如果输入为完整，请添加以下内容：

try{
    char initial = name.split(" ")[1].charAt(0);
} catch(Exception e){
   System.out.println("Invalid input!");
}

Answer 2

一个简单的解决方案是使用char的ascii值。

int m = (int)'M';
name = name.toUpperCase();
int initial = (int)name.charAt(0);

if(initial < m)
{
    System.out.println(" This student can sit anywhere in row 1. ");
}
else
{
    System.out.println(" This student can sit anywhere in row 2. ");
}

确定char值是否在chars范围内

2 个答案: