从SequenceType继承时所需的方法

Question

我正在查看SequenceType的协议声明，并且我想知道如何理解generate是SequenceType派生的类的唯一函数应该实现。

public protocol SequenceType {
    /// A type that provides the *sequence*'s iteration interface and
    /// encapsulates its iteration state.
    typealias Generator : GeneratorType
    /// A type that represents a subsequence of some of the elements.
    typealias SubSequence
    /// Return a *generator* over the elements of this *sequence*.
    ///
    /// - Complexity: O(1).
    @warn_unused_result
    public func generate() -> Self.Generator
    /// Return a value less than or equal to the number of elements in
    /// `self`, **nondestructively**.
    ///
    /// - Complexity: O(N).
    @warn_unused_result
    public func underestimateCount() -> Int
    /// Return an `Array` containing the results of mapping `transform`
    /// over `self`.
    ///
    /// - Complexity: O(N).
    @warn_unused_result
    @rethrows public func map<T>(@noescape transform: (Self.Generator.Element) throws -> T) rethrows -> [T]

我实现了一个派生自SequenceType的自定义类，在我添加对generate的支持之前，我收到了以下错误：

  

键入＆＃39; MySequenceClass＆＃39;不符合协议＆＃39; SequenceType＆＃39;

查看标题声明，我认为我必须实现此协议的所有方法，但显然我不是。阅读这些标题文档的诀窍是什么？