Question

我总是得到这条消息。“在一个非对象上调用成员函数errorInfo（）我用PDO连接数据库，它工作localhost服务器，但我需要连接到另一台服务器。这是我的代码：

class Database{

protected $db_name = "develop_for_me";
protected $host = "phpmyadmin.develop.forme";
protected $name = "develop_benj";
protected $password = "myname2015";
protected $conn;

function __construct()
{
    try {
        $this->conn = new PDO("mysql:host=" . $this->host.";dbname=".$this->db_name , $this->name, $this->password);

    } catch (PDOException $e) {
        $e->getMessage();
        print_r($this->conn->errorInfo());

    }
}

谢谢你的帮助！

Answer 1

您有此消息，因为您的错误处理错误。

使构造函数正确方式

function __construct()
{
    $this->conn = new PDO("mysql:host=" . $this->host.";dbname=".$this->db_name , $this->name, $this->password);
}

阅读错误消息并修复错误

Answer 2

<!DOCTYPE html>
<html>
<head>
    <script lang="javascript">
        var reusableHtml = "<div>  <table border='1'>    <tbody>        <tr>            <td>0</td>            <td>${spm}</td>       </tr>       <tr>            <td>A</td>            <td>B</td>       </tr>    </tbody> </table></div>";

        function pushReusbalecode(){
            alert('1');
            document.getElementById("demo1").innerHTML = reusableHtml;
            document.getElementById("demo2").innerHTML = reusableHtml;
        }

    </script> 
</head>
<body onload="pushReusbalecode()">

<div id="demo1"></div>

<br>##########################<br>

<div id="demo2"></div>

<br>##########################<br>

</body>        



</html>

Answer 3

当异常发生时，它会跳到catch块并且不会发生分配。不要忘记打印/回显消息

function __construct() {
    try {
        $this->conn = new PDO("mysql:host=" . $this->host.";dbname=".$this->db_name , $this->name, $this->password);
    } catch (PDOException $e) {
       echo $e->getMessage();
    }
}

Answer 4

所以我重写了代码：

try {
        $this->conn = new PDO("mysql:host=" . $this->host.";dbname=".$this->db_name , $this->name, $this->password);



    } catch (PDOException $e) {
            die("Could not connect to database");

    }

现在工作正常。

PDO错误消息：在非对象中调用成员函数errorInfo（）

4 个答案: