答案 0 :(得分:0)
注意:这没有使用Chumper / Datatable包,但它确实使用了jQuery数据表,因此可能有一些用处。
我是这样做的。在这种情况下,我有一张美式橄榄球队的桌子。每个小组都是一个会议的成员,该会议是该司的一部分。可以按团队名称,会议或部门对团队进行分类。下面是用于实现此目的的服务器端代码。此外,它们可以通过会议或部门进行过滤。
/*
* Route::get( 'api/v1/teams-table', 'APIController@teamsTable' );
*/
public function dataTable() {
// get the input parameters
$i = Input::all();
// parse the parameters and set default values
$draw = isset( $i[ 'draw' ] ) ? $i[ 'draw' ] : 1;
$start = isset( $i[ 'start' ] ) ? $i[ 'start' ] : 0;
$length = isset( $i[ 'length' ] ) ? $i[ 'length' ] : 10;
$search = isset( $i[ 'search' ][ 'value' ] ) && '' != $i[ 'search' ][ 'value' ] ? $i[ 'search' ][ 'value' ] : false;
$ordrby = isset( $i[ 'order' ] ) ? $i[ 'columns' ][ $i[ 'order' ][ 0 ][ 'column' ] ][ 'name' ] : '';
$ordrdr = isset( $i[ 'order' ] ) ? $i[ 'order' ][ 0 ][ 'dir' ] : 'asc';
$total = Team::count();
$filter = $total;
// get the data
if ( '' == $search ) {
switch( $ordrby ) {
case 'name':
$teams = Team::with( 'conferences', 'logo', 'conferences.division' )
->skip( $start )
->take( $length )
->orderBy( 'name', $ordrdr )
->get();
break;
case 'conference':
$teams = Team::with( 'conferences', 'logo', 'conferences.division' )
->join( 'conference_team', 'conference_team.team_id', '=', 'teams.id' )->join( 'conferences', 'conferences.id', '=', 'conference_team.conference_id' )
->orderBy( 'conferences.abbr', $ordrdr )
->skip( $start )
->take( $length )
->get();
break;
case 'division':
$teams = Team::with( 'conferences', 'logo', 'conferences.division' )
->skip( $start )
->take( $length )
->conference()
->division()
->orderBy( 'abbr', $ordrdr )
->get();
break;
default:
$teams = Team::with([ 'conferences', 'logo', 'conferences.division' ])
->skip( $start )
->take( $length )
->get();
}
} else {
$teams = Team::with( 'conferences', 'logo', 'conferences.division' )
->skip( $start )
->take( $length )
->where( 'name', 'LIKE', '%' . $search . '%' )
->orWhereHas( 'conferences', function( $q ) use ( $search ) {
$q->where( 'abbr', 'LIKE', '%' . $search . '%' )
->orWhereHas( 'division', function( $qu ) use ( $search ) {
$qu->where( 'abbr', 'LIKE', '%' . $search . '%' );
});
})
->get();
$filter = Team::with( 'conferences', 'logo', 'conferences.division' )
->where( 'name', 'LIKE', '%' . $search . '%' )
->orWhereHas( 'conferences', function( $q ) use ( $search ) {
$q->where( 'abbr', 'LIKE', '%' . $search . '%' )
->orWhereHas( 'division', function( $qu ) use ( $search ) {
$qu->where( 'abbr', 'LIKE', '%' . $search . '%' );
});
})
->count();
}
// loop through the retrieved data and format it to be returned as JSON
$data = [];
foreach ( $teams as $t ) {
$show = URL::route( 'admin.team.show', $t->slug );
$edit = URL::route( 'admin.team.depth_chart', $t->slug );
$data[] = [
'checkbox' => '<label><input type="checkbox" class="ace" value="' . $t->id . '" /><span class="lbl"></span></label>',
'logo' => '<img src="' . $t->logo->filename . '" alt="' . $t->name . ' logo" height="40">',
'name' => [
'display' => link_to_route( 'admin.team.show', $t->name, [ $t->slug ] ),
'filter' => $t->name,
'sort' => $t->name,
],
'conference' => [
'display' => link_to_route( 'admin.conference.show', $t->conferences[ 0 ]->abbr, [ $t->conferences[ 0 ]->slug ] ),
'filter' => $t->conferences[ 0 ]->name . ' ' . $t->conferences[ 0 ]->abbr,
'sort' => $t->conferences[ 0 ]->abbr,
],
'division' => [
'display' => link_to_route( 'admin.division.show', $t->conferences[ 0 ]->division->abbr, [ $t->conferences[ 0 ]->division->slug ] ),
'filter' => $t->conferences[ 0 ]->division->name . ' ' . $t->conferences[ 0 ]->division->abbr,
'sort' => $t->conferences[ 0 ]->division->abbr,
],
'site' => '<a target="_blank" href="' . $t->url . '">website <i class="fa fa-external-link"></i></a>',
'actions' => sprintf( $this->actions, $show, $edit, $show, $edit ),
];
}
$tdata = [
'draw' => $draw,
'recordsTotal' => $total, //consider caching or setting fixed value for this
'recordsFiltered' => $filter,
'data' => $data,
];
return Response::json( $tdata );
}
运气好的话,你可以调整这个例子以适应你的情况。希望这有帮助!
答案 1 :(得分:0)
这就是我的做法
n.b。它没有优化。或多或少没有错误检查的完整代码片段
laravel控制器功能(它是L5.2,但很容易降级到4.2):
$response = array();
$query = MyModel::query();
$response['recordsTotal'] = MyModel::count();
$response['draw'] = Input::get('draw', 0);
$query->where('searchField', 'LIKE', '%' . Input::get('search', array('value' => ''))['value'] . '%');
$response['recordsFiltered'] = $query->count();
$query->take(Input::get('length', 1));
$query->offset(Input::get('start', 0));
$columns = Input::get('columns');
$orders = Input::get('order', []);
$data = $data->toArray();
foreach($orders as $order){
$idx = $order['column'];
$column = $columns[$idx];
$orderFactor = 1;
if($order['dir'] == 'desc')
$orderFactor = -1;
$dname = $column['data'];
if(count($data)>0){
if(isset($data[0][$dname])){
usort($data, function($record1, $record2) use($dname, $orderFactor){
// here you implement your custom sorting
// like if($dname === 'price') return compare_price($record1[$dname], $record2[$dname]) * $orderFactor;
// but I hope you're not storing prices as strings in your database. you won't need this custom sorting
//
return strcmp($record1[$dname], $record2[$dname]) * $orderFactor;
});
}
}
}
$response['data'] = $data;
return Response::json($response);
P.S。此代码假定数据表列的“data”字段与数据库中的字段名称完全相同。 您还需要使用render_function来根据需要呈现数据表列
数据表列:
columns: [
{ data: 'price', orderable: true, searchable: true, render: render_price },
{ data: 'anotherField' },
[...]
],
render_function示例:
function render_price(price, type, row) {
return price + ' USD';
}
这样您就可以按照自己想要的方式显示列数据(例如,价格= 10.50 $)
它们将是可排序的
答案 2 :(得分:0)
如果您尝试按任何顺序对集合或查询结果进行排序,您可以执行以下操作:
$orders = Order::all()->SortBy('currency','desc');
或
$customers = Customers::where('age',$age)->orderBy('currency','desc')->get();
顺便说一句,既然已经有了 Laravel 8,你为什么还在 Laravel 4 上?
答案 3 :(得分:-1)
不确定custom sorting
是否意味着点击标题对行进行排序?如果这就是您的意思,那么您可以通过定义数据表设置在客户端定义它们。
oSettings = $("#{{$table->getId()}}").dataTable().fnSettings();
oSettings.aaSorting = [[6, 'desc']];
但是如果要在数据表加载时维护特定列的默认排序,那么
Datatable::table()
->addColumn($theader) // these are the column headings to be shown
->setOptions('order', array([$ordercolumn ,"desc"]))
->setUrl(route('route.name', $form_id))
->render()
我希望这会有所帮助。
答案 4 :(得分:-2)
public function getDatatable() { return Datatable::collection(User::all(array('id','name'))) ->showColumns('id', 'name') ->searchColumns('name') ->orderColumns('id','name') ->make(); }