Question

我已经尝试了一些与while循环相关的事情，似乎无法让它发挥作用。我想继续请求用户输入，直到用户输入数字0，这是我到目前为止的代码：

import java.util.*;

public class Task10 {

    public static void main(String[] args) {
        System.out.println("Enter a year to check if it is a leap year");
        Scanner input = new Scanner(System.in);
        int year = input.nextInt();

        if ((year % 4 == 0) || ((year % 400 == 0) && (year % 100 != 0)))
            System.out.println(year + " is a leap year");
        else
            System.out.println(year + " is not a leap year");
    }
}

Answer 1

在输入行上方使用while循环：

 while(true)

并使用if条件break。

if(year == 0)
    break;

此外，代码中leap year的条件错误。它应该是：

if((year % 100 == 0 && year % 400 == 0) || (year % 4 == 0 && year % 100 != 0))
    //its a leap year
else
    //its not

PS：在评论中，我将提供完整的代码：

import java.util.*;

public class Task10 {

public static void main(String[] args) {
    System.out.println("Enter a year to check if it is a leap year");
    while(true){
    Scanner input = new Scanner(System.in);
        int year = input.nextInt();
        if(year == 0)
            break;
        if((year % 100 == 0 && year % 400 == 0) || (year % 4 == 0 && year % 100 != 0))
            System.out.println(year + " is a leap year");
        else
            System.out.println(year + " is not a leap year");
    }
}

}

Answer 2

你应该把输入代码放在while循环中，然后循环，直到循环，直到0或更小。

None

Answer 3

你需要做一些事情让你的输入循环继续运行，直到遇到停止条件（在你的情况下是用户输入0时）

// First get the scanner object with the input stream
Scanner sc = new Scanner(System.in); 

// Just using do-while here for no reason, you can use a simple while(true) as well
do{
    int input = sc.nextInt();  // read the next input
    if (int == 0) { // check if we need to exit out
        // break only if 0 is entered, this means we don't want to run the loop anymore
        break;
    } else {
        // otherwise, do something with the input
    }
} while(true); // and keep repeating

我如何使用while循环来继续请求用户输入

3 个答案: