Question

我有一个数学计划，即对球员进行评分并输入他们的名字并将其分数到文本文件中。

我可以从文本文件中获取分数，但无法确定如何识别每个部分：名称为字符串，分数为int。

输入到这样的文件：

playername: 8

输入玩家姓名和得分到文本文件的代码是:(我已将得分设置为全局变量，并且它是从之前的函数中提取的。

# write score to text document
def scores():
    score = Pname + ": " +str(points)
    scoreFile = open("score.txt", "a")
    scoreFile.write(score + "\n")
    scoreFile.close()
    print("Your scores have been saved to the high score chart.\n")
close()

我试图解决它的多种方式只是给我数据。我努力将其拆分为名称和得分，然后按得分降序排列。

def highscore():
# --------------------------------------------
# sort scores from text file here
try:
    scores = open("score.txt", "r")
    for line in scores.readlines():
        line_parts = line.split(": ")
        if len(line_parts) > 1:
            line_parts = line_parts[-1].split("\n")
            score = line_parts[0]
        print(sorted(score))
except Exception:
    pass
# --------------------------------------------
close()

这只是显示如下分数：

['7']
['4']
['9']
['1']

我需要的是：

['Player 1: 9']
['Player 2: 7']
['Player 3: 4']
['Player 4: 1']

Answer 1

试试这个：创建一个排序方法并将整个列表提供给soreted方法。

  public static class addProjInfo_container {
    public static String projName_txt(WebDriver driver) {
        By by = By.xpath("//label[text()='Project Name']/following-sibling::input");
        driver.findElement(by);
        return getSelectorAsString(by);

    }

    public static String getSelectorAsString(By by) {
        String str = by.toString();
        return str.substring(str.indexOf(" ") , str.length());
      }
    // and so on for every text field for adding project...
}

<强>更新

我已更新代码并对其进行了测试。现在它有效。我一直在使用python2.7

更新：2

这很简单。只需将def highscore(): # -------------------------------------------- # sort scores from text file here try: scores = open("score.txt", "r") x = [] # place all your processed lines in here for line in scores.readlines(): line_parts = line.split(": ") if len(line_parts) > 1: line_parts[-1] = line_parts[-1].replace("\n", "") x.append(line_parts) # sorting uses lists print(sorted(x, key=sortByScore)) # get this out of for loop except Exception: pass # -------------------------------------------- close() def sortByScore(inputPlayerScore): return inputPlayerScore[1]命令移出print循环，您就可以获得所需的输出。

从文本文件和排名中读取高分

1 个答案: