Question

我有3组中的项目，我想生成如下例子的数组：

Group 1 = {m1, m2, m3}
Group 2 = {m4, m5}
Group 3 = {m6, m7, m8, m9}

{m1, m4, m6}
{m2, m5, m7}
{m3, null, m8}
{null, null, m9}

组中的每个元素只应在生成的数组中出现一次。我该如何处理这个问题？

Answer 1

您应该考虑做这样的事情（请记住这是伪代码）：

group1 = {m1, m2, m3}
group2 = {m4, m5}
group3 = {m6, m7, m8, m9}

len1 = group1.size
len2 = group2.size
len3 = group3.size

max = max(len1, len2, len3)

combination = {}
for i from 0 to max:

    combination = {}
    if(group1(i) exists)
        combination.add(group1(i))
    else combination.add("null")

    if(group2(i) exists)
        combination.add(group2(i))
    else combination.add("null")            

    if(group3(i) exists)
        combination.add(group3(i))
    else combination.add("null")            

    print combination

Answer 2

这就是我这样做的，它的maxscript代码分析了可以拥有其他多种材料的多种材料，并从每个ID创建新材料。也许我对第一次行动有点不清楚。

    local maxSubID = amax arrayNumSubs --it is the count of the array with highest number of items.


    for maxSubCounter = 1 to maxSubID do
    (
        tmpMat = multimaterial numsubs:mainMatIDs
        for subCounter = 1 to mainMatIDs do
        (
            if (rootMat[subCounter] != undefined) then
            (
                tmpMat[subCounter] = rootMat[subCounter][maxSubCounter]
            )else
            (
                tmpMat[subCounter] = undefined
            )
        )
        append materialsToApply tmpMat
    )

组项目的组合，没有重复

2 个答案: