我正在尝试用4件套装制作一副52张牌:黑桃,心形,棍棒和钻石。我试图在我的Deck类中创建这个for循环,但似乎遇到了一些关于实际让程序按我想要做的问题。我想也许我可以做4个for循环,但是可以使用if / else-ifs在套牌中创建4个套装吗?
class Deck
{
private Card[] cards;
public Deck()
{
cards = new Card[52];
int check = 0;
for (int suitVal = 1; suitVal < 4; suitVal++)
{
for (int rankVal = 1; rankVal < 14; rankVal++)
{
if(suitVal == 1)
{
cards[check] = new Card(rankVal, "Spades");
}
else if (suitVal == 2)
{
cards[check] = new Card(rankVal, "Hearts");
}
else if (suitVal == 3)
{
cards[check] = new Card(rankVal, "Clubs");
}
else if (suitVal == 4)
{
cards[check] = new Card(rankVal, "Diamonds");
}
}
}
}
答案 0 :(得分:5)
是的,有可能。 共有13张牌和4件套装。这个想法是,对于每件套装,你创造了13张带有所述套装的卡片。伪代码几乎就是你已经拥有的东西:
for each of the four suits
loop 13 times for said suit
以下是您的代码存在的问题:
1-您的check
变量永远不会增加,因此您始终会覆盖位置0上的卡片;每插入一张卡(内循环)后它应该递增
2-你的外围循环只运行3次(i = 1,i = 2,i = 3),并且有4套西装。
如果您需要更多帮助,请与我联系。
答案 1 :(得分:2)
你可以这样做:
class Deck
{
private Card[] cards;
public Deck()
{
cards =
new [] { "Spades", "Hearts", "Clubs", "Diamonds", }
.SelectMany(
suit => Enumerable.Range(1, 13),
(suit, rank) => new Card(rank, suit))
.ToArray();
}
}
或者:
class Deck
{
private Card[] cards;
public Deck()
{
var query =
from suit in new [] { "Spades", "Hearts", "Clubs", "Diamonds", }
from rank in Enumerable.Range(1, 13)
select new Card(rank, suit);
cards = query.ToArray();
}
}
或者:
class Deck
{
private Card[] cards;
public Deck()
{
cards = new Card[52];
var index = 0;
foreach (var suit in new [] { "Spades", "Hearts", "Clubs", "Diamonds", })
{
for (var rank = 1; rank <= 13; rank++)
{
cards[index++] = new Card(rank, suit);
}
}
}
}