Question

最初我想在现有的UISearchBar旁边的Main.storyboard上添加一个隐藏的UIPickerView，当点击一个BarButtonItem时，应该显示UIPickerView;但似乎我不能在给定的空间内同时拥有它们。

相反，我最好的选择是以编程方式创建它。我已经按照现有的教程（http://sourcefreeze.com/ios-uipickerview-example-using-swift/）和类似的问题（Programmatically Create and Show UIPickerView）看起来我（？）有一个UIPickerView，因为它的描述正在打印，我得到以下内容：

<UIPickerView: 0x7f86425b1fb0; frame = (100 100; 100 162); layer = <CALayer: 0x7f8642543a20>>

以下是我当前代码的一部分，可能会有所帮助：

AnimalTableViewController.swift

import UIKit

class AnimalTableViewController: UITableViewController, UINavigationControllerDelegate, UISearchBarDelegate, UISearchDisplayDelegate, UISearchResultsUpdating, UIPickerViewDelegate, UIPickerViewDataSource {

    @IBOutlet var segmentedSortOption: UISegmentedControl!
    var array : NSArray = Animal.animalStruct.jsonResult["animal"] as NSArray
    var filteredArray = [[String:AnyObject]]()
    var timer = NSTimer()
    var counter:Int = 1
    var typePickerView: UIPickerView = UIPickerView()

    @IBOutlet var typeBarButton: UIBarButtonItem!
    var resultSearchController = UISearchController()

    var indexArray:String!

    @IBAction func refresh(sender: AnyObject) {

        self.tableView.reloadData()
        println("refreshed")
    }

    override func viewDidLoad() {
        super.viewDidLoad()

        self.typePickerView.hidden = true
        self.typePickerView.dataSource = self
        self.typePickerView.delegate = self
        self.typePickerView.frame = CGRectMake(100, 100, 100, 162)
        self.typePickerView.backgroundColor = UIColor.blackColor()
        self.typePickerView.layer.borderColor = UIColor.whiteColor().CGColor
        self.typePickerView.layer.borderWidth = 1        
        timer = NSTimer.scheduledTimerWithTimeInterval(0.2, target: self, selector: Selector("result"), userInfo: nil, repeats: true)

        self.resultSearchController = ({
            let controller = UISearchController(searchResultsController: nil)
            controller.searchResultsUpdater = self
            controller.dimsBackgroundDuringPresentation = false
            controller.searchBar.sizeToFit()

            self.tableView.tableHeaderView = controller.searchBar

            return controller
        })()
    }

    func numberOfComponentsInPickerView(pickerView: UIPickerView) -> Int {
        return 1
    }

    func pickerView(pickerView: UIPickerView, numberOfRowsInComponent component: Int) -> Int {
        return array.count
    }

    func pickerView(pickerView: UIPickerView, titleForRow row: Int, forComponent component: Int) -> String! {
        return array[row]["type1"] as String
    }

    func pickerView(pickerView: UIPickerView, didSelectRow row: Int, inComponent component: Int) {
        typeBarButton.title = array[row]["type1"] as? String
        typePickerView.hidden = false
    }

    func pickerView(pickerView: UIPickerView, widthForComponent component: Int) -> CGFloat {
        return 36.0
    }

    func pickerView(pickerView: UIPickerView, rowHeightForComponent component: Int) -> CGFloat {
        return 36.0
    }

    @IBAction func typePickerViewSelected(sender: AnyObject) {
        typePickerView.hidden = false
        println(typePickerView.description)
    }

}

请问在按下BarButtonItem时，是否可以帮助我显示以编程方式创建的UIPickerView？如果您还有其他问题，请询问。

非常感谢。

Answer 1

您永远不会将pickerView添加为ViewController的子视图，您可以在viewDidLoad()中执行，因为您要隐藏它。然后，当你取消隐藏它时，你的观点就应该存在。

编辑：添加代码

override func viewDidLoad() {
    super.viewDidLoad()
    self.typePickerView.hidden = true
    //other pickerView code like dataSource and delegate
    self.view.addSubview(pickerView) //will add the subview to the view hierarchy
}

使用上面的代码，现在当您在按钮上取消隐藏它时，视图将显示出来。

Swift - 按下BarButtonItem时以编程方式创建和显示UIPickerView

1 个答案: