我需要一些帮助,确保当用户输入任何内容或不输入数字时,它不会崩溃。我把它弄下来,如果他们没有,它会告诉他们输入一个数字,但我不知道如何让它回到原来的问题并给他们一个正确输入的机会。谢谢你的帮助。
Console.WriteLine("How much is rent: ");
string strRent = Console.ReadLine();
double dblRent = 0.0;
if (double.TryParse(strRent, out dblRent))
{
Console.WriteLine("How much is the car payment: ");
string strCarPayment = Console.ReadLine();
double dblCarPayment = Convert.ToDouble(strCarPayment);
}
else
{
Console.WriteLine("Enter a number");
}
Console.WriteLine("How much is student loan payment: ");
string strStudentLoan = Console.ReadLine();
Console.WriteLine("How much is phone bill: ");
string strPhoneBill = Console.ReadLine();
Console.WriteLine("How much is electric bill: ");
string strElectricBill = Console.ReadLine();
Console.WriteLine("Fraction deposited: ");
string strFractionDeposited = Console.ReadLine();
Console.WriteLine("Amount leftover: ");
string strAmountLeft = Console.ReadLine();
double dblStudentLoan = Convert.ToDouble(strStudentLoan);
double dblPhoneBill = Convert.ToDouble(strPhoneBill);
double dblElectricBill = Convert.ToDouble(strElectricBill);
double dblFractionDeposited = Convert.ToDouble(strFractionDeposited);
double dblAmountLeft = Convert.ToDouble(strAmountLeft);
double dblBillSum = dblRent + dblCarPayment + dblStudentLoan + dblPhoneBill + dblElectricBill;
double afterBills = dblAmountLeft / (1 - dblFractionDeposited);
double totalPaycheck = afterBills + dblBillSum;
Console.WriteLine("Total Paycheck: " + totalPaycheck.ToString("C"));
Console.WriteLine("Enter wage $/hr: ");
string strWage = Console.ReadLine();
Console.WriteLine("Enter hours worked overtime: ");
string strHoursOT = Console.ReadLine();
Console.WriteLine("Enter overtime multiplier: ");
string strOTWage = Console.ReadLine();
double dblWage = Convert.ToDouble(strWage);
double dblHoursOT = Convert.ToDouble(strHoursOT);
double dblOTWage = Convert.ToDouble(strOTWage);
double OTPay = (dblWage * dblOTWage) * dblHoursOT;
Console.WriteLine("Overtime Pay: " + OTPay.ToString("C"));
Console.ReadLine();
}
}
}
答案 0 :(得分:2)
你需要一个循环,就像这样
Console.WriteLine("How much is rent: ");
string strRent = Console.ReadLine();
double dblRent = 0.0;
while (!double.TryParse(strRent, out dblRent))
{
Console.WriteLine("Enter a number");
strRent = Console.ReadLine();
}
Console.WriteLine("How much is the car payment: ");
string strCarPayment = Console.ReadLine();
double dblCarPayment = Convert.ToDouble(strCarPayment);
答案 1 :(得分:0)
试试这个
double dblRent = 0.0;
Boolean valid = false;
while (!valid)
{
if (double.TryParse(strRent, out dblRent))
{
Console.WriteLine("How much is the car payment: ");
string strCarPayment = Console.ReadLine();
double dblCarPayment = Convert.ToDouble(strCarPayment);
valid = true;
}
else
{
Console.WriteLine("Enter a number");
}
}

答案 2 :(得分:0)
由于您正在阅读许多双打,因此您可以创建一个封装读取和处理数字的方法
private static double? ReadLineDouble()
{
while(true) {
string s = Console.ReadLine();
if (String.IsNullOrWhitespace(s)) {
return null; // The user wants to abort
}
double d;
if (Double.TryParse(s, out d)) {
return d;
}
Console.WriteLine("Please enter a valid number");
}
}
如果用户只是点击Enter
,他可能想要中止。在这种情况下,该方法返回null
。这是可能的,因为返回类型是Nullable<double>
。它的简写符号是double?
。
现在你可以阅读这样的数字:
double? rent = ReadLineDouble();
if (double == null) return; // Abort the program.
// Otherwise continue.