我在Python中使用HTML看起来像这样。我正在使用lxml解析,但同样可以愉快地使用pyquery:
<p><span class="Title">Name</span>Dave Davies</p>
<p><span class="Title">Address</span>123 Greyfriars Road, London</p>
拔出'姓名'和'地址'很容易,无论我使用哪个库,但我如何获得剩下的文字 - 即'戴夫戴维斯'?
答案 0 :(得分:2)
另一种方法 - 使用xpath:
>>> from lxml import html
>>> doc = html.parse( file )
>>> doc.xpath( '//span[@class="Title"][text()="Name"]/../self::p/text()' )
['Dave Davies']
>>> doc.xpath( '//span[@class="Title"][text()="Address"]/../self::p/text()' )
['123 Greyfriars Road, London']
答案 1 :(得分:1)
每个元素都可以有一个text and a tail attribute(在链接中,搜索单词“tail”):
import lxml.etree
content='''\
<p><span class="Title">Name</span>Dave Davies</p>
<p><span class="Title">Address</span>123 Greyfriars Road, London</p>'''
root=lxml.etree.fromstring(content,parser=lxml.etree.HTMLParser())
for elt in root.findall('**/span'):
print(elt.text, elt.tail)
# ('Name', 'Dave Davies')
# ('Address', '123 Greyfriars Road, London')
答案 2 :(得分:0)
看看BeautifulSoup。我刚刚开始使用它,所以我不是专家。在我的头顶:
import BeautifulSoup
text = '''<p><span class="Title">Name</span>Dave Davies</p>
<p><span class="Title">Address</span>123 Greyfriars Road, London</p>'''
soup = BeautifulSoup.BeautifulSoup(text)
paras = soup.findAll('p')
for para in paras:
spantext = para.span.text
othertext = para.span.nextSibling
print spantext, othertext
[Out]: Name Dave Davies
Address 123 Greyfriars Road, London