Question

如果用户正确键入屏幕上的内容，我就会拥有这段代码。

 -keep class com.google.android.gms.** { *; }
 -dontwarn com.google.android.gms.**

我想知道如果他们不键入屏幕上的内容，如何阻止这段代码运行：

words = ["Games","Development","Keyboard","Speed","Typer","Anything","Alpha","Zealous","Accurate","Basics","Shortcut","Purpose","Window","Counter","Fortress","Modification","Computer","Science","History","Football","Basketball","Solid","Phantom","Battlefield","Advanced","Warfare","Download","Upload","Antidisestablishmentarianism","Supercalifragilisticexpialidocious","Discomobobulation","Liberated","Assassin","Brotherhood","Revelation","Unity","Syndicate","Victory"]
wordcount = 0
maxwords = 12        
skips = 0

def nextWord():
        global score
        global wordcount
        global skips
        global maxwords
        global name
        global high_score

        entry.focus_set()

        if entry.get().lower() == words[1].lower():
            score += 1
            wordcount += 1
            wordcounter.config(text="Words: " + str(wordcount))

即使因为以下原因而未正确输入，它仍会继续：

        for i in range(maxwords):
            entry.delete(0, tkinter.END)
            random.shuffle(words)
            label.config(text=str(words[1]))
            scoreLabel.config(text="Time: " + str(score)+ "s")

我目前有这个：

def startGame(event):
    nextWord()

root.bind("<Return>", startGame)

目前的做法是制作

    elif entry.get().lower() != words[1].lower():
            wronglabel.config(text="WRONG!")
            time.sleep(0.6)
            wronglabel.delete(0, tkinter.END)

说错了但我想知道如果用户没有输入正确的单词，如何使其不随机随机播放并从列表中获取项目。感谢。

总之，这使得:(仅发布相关代码）：

wronglabel = tkinter.Label(root, text="", font =("Helvetica, 14"))
wronglabel.pack()

（我在代码中编辑了一些小问题来解决另一个问题）

Answer 1

我可能只是没有正确理解这一点，但是你不能像这样在if语句中移动for循环吗？

if entry.get().lower() == words[1].lower():
    score += 1
    wordcount += 1
    wordcounter.config(text="Words: " + str(wordcount))

    for i in words[len(maxwords)]:
        entry.delete(0, tkinter.END)
        random.shuffle(words)
        label.config(text=str(words[1]))
        scoreLabel.config(text="Time: " + str(score)+ "s")

一旦按下错误的键，如何停止发生代码块

1 个答案: