Question

我的目标是从/photos/

中提取$file之后的用户名

$file = '/photos/plant_a/sort,"1,528","1,278",00:10:21,"1,263"
     /photos/forest-b/nosort,"1,528","1,278",00:10:21,"1,263"
     /photos/soil_c1/,"1,528","1,278",00:10:21,"1,263"
     /photos/jungle_c2,"1,528","1,278",00:10:21,"1,263"';

preg_match_all('~/photos/(.+?)/~', $file, $matches);
print_r($matches[1]);

此选项仅输出plant_a，forest-b和soil_c1，但不输出jungle_c2。

这些是用户名，可以包含_，-和数字。一旦出现逗号，就意味着该URL的结尾。

如何提取juncle_c2？

Answer 1

我认为这是有效的

inside findMyLocation * inside didUpdateLocations * Latitude: -26.204103 Longitude: 28.0473051inside sendDataToServer * inside didUpdateLocations * Latitude: -26.204103 Longitude: 28.0473051inside sendDataToServer * inside didUpdateLocations * Latitude: -26.204103 Longitude: 28.0473051inside sendDataToServer *

编辑（因为有关换行符的评论）：~/photos/([^/]+)~

第二次编辑（自下次评论以来）：~/photos/([^/\r\n]+)~

正则表达式提取单词

1 个答案: