Question

我需要在mysql的视图中使用的表列表。例如，如果我有一个类似的视图：

SELECT * FROM table1
JOIN  table2
ON table1.id = table2.id

我想得到：table1，table2

Answer 1

mysql> CREATE VIEW vw_test AS  
    -> SELECT * FROM table1 JOIN table2 ON table1.id = table2.id;
Query OK, 0 rows affected (0.00 sec)

mysql> SELECT VIEW_DEFINITION FROM INFORMATION_SCHEMA.VIEWS
    -> WHERE TABLE_NAME = 'vw_test';
+------------------------------------------------------------------+
| VIEW_DEFINITION                                                  |
+------------------------------------------------------------------+
| select * from table1 join table2 on table1.id = table2.id;       |
+------------------------------------------------------------------+
1 row in set (0.00 sec)

然后您可以使用以下任何工具来解析表名：

Terence Parr的ANTLR解析器生成器（Java，但可以使用多种目标语言中的任何一种生成解析器）有几种可用的SQL语法，包括一对用于PL / SQL，一种用于SQL Server SELECT语句，一个用于mySQL，一个用于ISO SQL - （http://www.antlr.org/grammar/list）。

我从这里回答：SQL parser library for Java - Retrieve the list of table names present in a SQL statement
Data Tools Project - SQL Development Tools（http://www.eclipse.org/datatools/project_sqldevtools/）。

以下是SQL Query Parser（http://www.eclipse.org/datatools/project_sqldevtools/sqltools_doc/SQL%20Query%20Parser%20User%20documentation.htm）的文档。
这是一个博客，其中介绍了如何“Get columns and tables in SQL script (Java version)”http://www.dpriver.com/blog/list-of-demos-illustrate-how-to-use-general-sql-parser/get-columns-and-tables-in-sql-script/

或者根据以下内容编写自定义mySQL proc（在此处找到 - http://www.sqlparser.com/fetch-table-column-name-example-extact-all-table-field-name.php）：

SELECT c_mandant, hist_datum, parkey1, parkey2, funktionscode, ma_parkey, me_parkey 
 , CASE WHEN EXISTS (SELECT 1 
                       FROM CDS_H_GRUPPE  GRP1 
                      WHERE GRP1.c_mandant = c_mandant 
                        AND GRP1.hist_datum    = ADD_MONTHS(LAST_DAY(TRUNC(SYSDATE)), -1) 
                        AND GRP1.funktionscode = 'H' 
                        AND GRP1.parkey1       = ma_parkey) 
          THEN 1 
      ELSE NULL 
   END MA_ME 
 , CASE WHEN EXISTS (SELECT 1 
                       FROM CDS_H_GRUPPE    GRP2 
                      WHERE GRP2.c_mandant     = c_mandant 
                        AND GRP2.hist_datum    = ADD_MONTHS(LAST_DAY(TRUNC(SYSDATE)), -1) 
                        AND GRP2.funktionscode = 'U' 
                        AND GRP2.parkey1       = me_parkey) 
          THEN 1 
      ELSE NULL 
   END ME_MA 
 , ROW_NUMBER() OVER (PARTITION BY c_mandant, ma_parkey, me_parkey ORDER BY c_mandant, ma_parkey, me_parkey)  ANZ_MA 
  FROM (SELECT c_mandant, hist_datum, parkey1, parkey2, funktionscode 
         , CASE WHEN funktionscode = 'U' 
                  THEN parkey1 
              ELSE parkey2 
           END MA_PARKEY 
         , CASE WHEN funktionscode = 'U' 
                  THEN NULL 
              ELSE parkey1 
           END ME_PARKEY 
      FROM 
           CDS_H_GRUPPE 
     WHERE 
           funktionscode IN ('U', 'H') 
       AND hist_datum    = ADD_MONTHS(LAST_DAY(TRUNC(SYSDATE)), -1) 
   )

Answer 2

不幸的是，我不相信这是可能的。相反，您需要查询和解析实际的视图定义：

SELECT VIEW_DEFINITION
FROM INFORMATION_SCHEMA.VIEWS
WHERE
TABLE_NAME = ?;

Answer 3

否这是不可能的。您必须查找视图的定义并手动完成。

Answer 4

这就是您想要的...这可以使Views中使用的表和联接在一起的表..但是它可以得到一个联接...如果要更多，则添加更多提示。.

希望这可以解决您的问题...

select 
    case 
        when view_definition regexp '.*from +.*'
        then substring_index(substring_index(view_definition, 'from ', -1), ' ', 1)
    end as 'primary table',
    case 
        when view_definition regexp '.*join +.*'
        then substring_index(substring_index(view_definition, 'join ', -1), ' ', 1)
    end as 'joined table'
from information_schema.views where table_name="YOUR VIEW NAME" and table_schema="shotbot_production";

如何使用mysql

4 个答案: