我想在Safari中登录Instagram,并希望在ios应用程序中对其进行响应。
我已经从iPhone应用程序重定向到Safari for Instagram登录。 现在我想在iPhone应用程序中获取Safari登录Safari的响应数据。
我不知道。这可能吗?我们可以在iOS应用程序中获得Safari URL的响应吗?
答案 0 :(得分:1)
为此你必须使用UIWebView及其委托方法。
来自Instagram-Auth-iOS的代码
- (BOOL)webView:(UIWebView *)webView shouldStartLoadWithRequest:(NSURLRequest *)request navigationType:(UIWebViewNavigationType)navigationType
{
NSString *responseURL = [request.URL absoluteString];
NSString *urlCallbackPrefix = [NSString stringWithFormat:@"%@/?code=", INSTAGRAM_CALLBACK_BASE];
//We received the code, now request the auth token from Instagram.
if([responseURL hasPrefix:urlCallbackPrefix])
{
NSString *authToken = [responseURL substringFromIndex:[urlCallbackPrefix length]];
NSURL *url = [NSURL URLWithString:@"https://api.instagram.com/oauth/access_token"];
NSMutableURLRequest *request = [[NSMutableURLRequest alloc] initWithURL:url];
NSDictionary *paramDict = [NSDictionary dictionaryWithObjectsAndKeys:authToken, @"code", INSTAGRAM_CALLBACK_BASE, @"redirect_uri", @"authorization_code", @"grant_type", INSTAGRAM_CLIENT_ID, @"client_id", INSTAGRAM_CLIENT_SECRET, @"client_secret", nil];
NSString *paramString = [paramDict urlEncodedString];
NSString *charset = (NSString *)CFStringConvertEncodingToIANACharSetName(CFStringConvertNSStringEncodingToEncoding(NSUTF8StringEncoding));
[request setHTTPMethod:@"POST"];
[request addValue:[NSString stringWithFormat:@"application/x-www-form-urlencoded; charset=%@",charset] forHTTPHeaderField:@"Content-Type"];
[request setHTTPBody:[paramString dataUsingEncoding:NSUTF8StringEncoding]];
self.tokenRequestConnection = [[NSURLConnection alloc] initWithRequest:request delegate:self];
[self.tokenRequestConnection start];
return NO;
}
return YES;
}
Github上的这个回购Instagram-Auth-iOS将帮助你