大家好我是PHP的新手，需要一点帮助来解决我的问题。如果已经讨论过，我会道歉。我有一个简单的webform，有两个字段。填写这些字段后，用户单击提交按钮，数据应存储在数据库中。但是由于我不知道的原因，我无法存储它。
这是我的index.php：
<html lang="en">
<head>
<meta charset="utf-8">
<title> INSERTING DATA TO DATABASE!!! </title>
<link rel="stylesheet" href="../CSS/testbox.css" type="text/css"/>
<!-- Style sheet for form -->
</head>
<body>
<form action="../PHP/test.php" method="post">
<div class="container">
<p class="header">Title *</p>
<input class="singleline" type="text" name="Title">
<p class="footer">Meaningful, short descriptive title</p>
<p class="header">Summary *</p>
<textarea name="Summary"></textarea>
<p class="footer">Brief summary of what the engagement involved.</p>
<br>
<input class="submit" type="submit" name="submit">
</div>
</form>
</body>
</html>
这是mytest.php：
<?php
$username = "root";
$password = "root";
$hostname = "127.0.0.1:80";
$dbname = "casestudy";
$dbcon = mysqli_connect($hostname, $username, $password, $dbname);
if (!dbcon)
{
die ('error connecting to database');
}
echo 'you have connected successfully';
if(isset($_POST['submit']))
{
$Title= $_POST['Title'];
$Summary= $_POST['Summary'];
echo " this is a $Title and this is a $Summary !";
$sql = "INSERT INTO example (title, summary) VALUES ('$Title', '$Summary')";
$result = mysqli_query($sql);
if ($result){
echo "<script type='text/javascript'>alert('submitted successfully!')</script>";
}
else
{
echo "<script type='text/javascript'>alert('failed!')</script>";
}
}
?>
我的问题是最后一步，当它试图将其保存到数据库时，我收到消息＆＃34;失败！＆＃34;而且我不知道我的错误在哪里。 非常感谢您的帮助。