我遇到的问题是如何让我的游戏停止“重新打印”棋盘游戏而不是在控制台的每一轮/转弯中反复显示棋盘?我希望它改变第一块板子中的“X”,而不是用“X”重新打印板。
以下是代码:
from random import randint
board = []
for x in range(5):
board.append(["O"] * 5)
def print_board(board):
for row in board:
print " ".join(row)
print "Let's play Battleship!"
print_board(board)
def random_row(board):
return randint(0, len(board) - 1)
def random_col(board):
return randint(0, len(board[0]) - 1)
ship_row = random_row(board)
ship_col = random_col(board)
print ship_row
print ship_col
for turn in range(4):
guess_row = int(raw_input("Guess Row:"))
guess_col = int(raw_input("Guess Col:"))
if guess_row == ship_row and guess_col == ship_col:
print "Congratulations! You sunk my battleship!"
break
else:
if (guess_row < 0 or guess_row > 4) or (guess_col < 0 or guess_col > 4):
print "Oops, that's not even in the ocean."
elif(board[guess_row][guess_col] == "X"):
print "You guessed that one already."
else:
print "You missed my battleship!"
board[guess_row][guess_col] = "X"
print "Turn", turn + 1
print_board(board)
print "Game Over"
答案 0 :(得分:4)
如果你想简单一点,你可以用这一行清除屏幕:
print(chr(27) + "[2J")
然后迅速重新粉刷董事会。
对于更高级的控制台管理,您可以使用curses
模块。它不是很容易使用,但它会让你做很多花哨的东西。它实际上是C curses
库的精简绑定,因此如果您搜索C语言库,可能会发现更多文档。
如果您想要图形,标准库是pygame
。它是流行的SDL库的一个不那么薄的绑定,但你会发现很多pygame
例子。