Question

我的模型是患者 - ＆gt; Sample-＆gt; Ready_Sample，关系都是oneToMany，我的问题是我查询Ready_Sample需要知道patient.name

Patient_Model

class Patient_Model extends Base_Model {

    protected $table = 'patients';

    public function samples(){
        return $this->hasMany('App\Models\Sample_Model','patient_id','code');
    }   
}

Sample_Model

class Sample_Model extends Base_Model{

    protected $table = 'samples';

    public function patient(){
        return $this->belongsTo('App\Models\Patient_Model','patient_id','code');
    }

    public function ready_samples(){
        return $this->hasMany('App\Models\Ready_Sample_Model','sample_id','code');
    }
}

Ready_Sample_Model

class Ready_Sample_Model extends Model{

    protected $table = 'ready_samples';

    public function sample(){
        return $this->belongsTo('App\Models\Sample_Model','sample_id','code');
    }
}

在Sample_Controller中

class Sample_Controller extends Controller{

    public function query(Request $request){

    $result = Sample_Model::with(['patient']);
        ->orderBy("updated_at","desc")
        ->Paginate(15)
        ->toJson();
   return $result;
}

在Sample中我知道得到patient.name，但Ready_Sample如何获得Patien.name？

Answer 1

您可以使用以下代码获取patient.name：

$readySample = Ready_Sample_Model::first(); // fetch the first record

echo $readySample->sample->patient->name;

希望它有所帮助！

Laravel5.1查询关系（Eloquent ORM）

1 个答案: