我有一个家庭作业,要求我实现自己的Linux shell。其中一部分要求我实现在同一命令中重定向输入和输出重定向的功能。
我得到"排序:读取失败: - :错误的文件描述符"尝试运行sort<时出错"文件名" > "文件名&#34 ;.任何帮助表示赞赏!
int dualRedirect(char *toks[], string uCommand) {
int stats;
int fd;
int fd1;
int size;
vector<string> file;
string inFileName;
string outFileName;
string buffer;
int stdIn = dup(0);
int stdOut = dup(1);
stringstream stream(uCommand);
// Convert the command string to a vector
while (stream >> buffer)
file.push_back(buffer);
// Identify the size of the vector in order to identify the output filename
size = file.size();
outFileName = toks[size - 1];
// Find "<" in order to find the input filename, then set it to NULL in order
// to pass the appropriate args to the exec command
for (int ii = 0; toks[ii] != NULL; ii++) {
if (!strcmp(toks[ii], "<")) {
inFileName = toks[ii + 1];
toks[ii] = NULL;
}
}
// Open the input file and assign it to the fd variable
if ((fd = open(inFileName.c_str(), O_CREAT | O_WRONLY )) == -1) {
cerr << strerror(errno);
return 1;
}
// Set STDIN to the fd variable (redirect stdin to fd)
if (dup2(fd, STDIN_FILENO) == -1) {
return 1;
}
// Open the output filename and assign it to fd1
if ((fd1 = open(outFileName.c_str(), O_CREAT | O_WRONLY )) == -1) {
cerr << strerror(errno);
return 1;
}
// Set STDOUT to the fd1 variable (redirect stdout to fd1)
if (dup2(fd1, 1) == -1) {
cerr << strerror(errno);
return 1;
}
// Close the original fd file
if (close(fd) == -1) {
cerr << strerror(errno);
return 1;
}
// Close the original fd1 file
if (close(fd1) == -1) {
cerr << strerror(errno);
return 1;
}
// fork and execute, passing the command and args to exec.
if (fork()) {
waitpid(-1, &stats, NULL);
}
else {
execvp(toks[0], toks);
exit(-1);
}
// Restore the stdin and stdout file descriptors to their original values
dup2(stdIn, 0);
dup2(stdOut, 1);
return 1; }
答案 0 :(得分:1)
更改
if ((fd = open(inFileName.c_str(), O_CREAT | O_WRONLY )) == -1) {
为:
if ((fd = open(inFileName.c_str(), O_RDONLY )) == -1) {
&#34;错误的文件描述符&#34;的原因之一错误是试图从不打开的描述符中读取。