Question

我有一个问题是在电子邮件视图中建立一个链接，~~它不会因为某些原因而把我从控制器传递的URL ...~~ 我传递给视图的网址字符串缺少http://domain前缀

usersController中的一些操作：

           $email = new Email(['gmail','transport'=>'gmail']);
           $email->template('recover', 'default')
                ->emailFormat('html')
                ->viewVars([
                    'username' => $user['username'],
                    'url' =>   '/users/resetpwd/u/'.$user['username'].'/t/'.$user['token']                      
                ])
                ->from(['mailer@domain.com' => 'My Site'])
                ->to('example@domain.com')
                ->subject('Password recovery')
                ->send()

recover.ctp：

<p>Welcome <b><?= $username; ?></b>,<br/>
 you requested a password change.<br/>
 To set a new password, please: <?php echo $this->Html->link('Click Here', $url, ['_full' => true,'escape' => true]); ?></p>
<?= $this->Html->image('banniere.gif', array('fullBase' => true));?><br/>
<p>This email was sent from <a href="http://cakephp.org">My Site</a></p>

Answer 1

如果您想确保网址始终是＆＃34;完整的＆＃34;一，那么这里适当的解决方案是Router::url()。这样你甚至可以用数组格式声明URL（通常应该是首选的样式）而不会破坏。

use Cake\Routing\Router;
// ...
<?= $this->Html->link('Click Here', Router::url($url, true), ['escape' => true]); ?>

cakePHP 3链接在电子邮件视图中

1 个答案: