我有一个富文本框,我希望能够像BORD,ITALIC,UNDERLINE以及它们的任意组合一样使用WORD等样式。
我可以使用下面的代码添加和删除说BOLD样式,我也可以添加多个样式,但如果我设置了多个样式并尝试删除一个没有任何发生。
样式更改代码:
Private Sub Underline_Text(rtBox As RichTextBox)
Dim newStyle As FontStyle
If rtBox.SelectionFont.Style = FontStyle.Underline Then
newStyle = rtBox.SelectionFont.Style And Not FontStyle.Underline
Else
newStyle = rtBox.SelectionFont.Style Or FontStyle.Underline
End If
Dim newFont As New Font(rtBox.SelectionFont.Name, rtBox.SelectionFont.Size, newStyle)
rtBox.SelectionFont = newFont
End Sub
完整代码:
Private Sub rtbDesc_KeyDown(sender As Object, e As KeyEventArgs) Handles rtbDesc.KeyDown
If e.Control AndAlso Not e.Alt AndAlso Not e.Shift Then
Select Case e.KeyCode.ToString
Case "B"
Bold_Text(DirectCast(sender, RichTextBox))
e.SuppressKeyPress = True
Case "I"
Italics_Text(DirectCast(sender, RichTextBox))
e.SuppressKeyPress = True
Case "U"
Underline_Text(DirectCast(sender, RichTextBox))
e.SuppressKeyPress = True
Case "R"
Reset_Text(DirectCast(sender, RichTextBox))
e.SuppressKeyPress = True
Case "K"
Strikeout_Text(DirectCast(sender, RichTextBox))
e.SuppressKeyPress = True
End Select
End If
End Sub
Private Sub Bold_Text(rtBox As RichTextBox)
Dim newStyle As FontStyle
If rtBox.SelectionFont.Style = FontStyle.Bold Then
newStyle = rtBox.SelectionFont.Style And Not FontStyle.Bold
Else
newStyle = rtBox.SelectionFont.Style Or FontStyle.Bold
End If
Dim newFont As New Font(rtBox.SelectionFont.Name, rtBox.SelectionFont.Size, newStyle)
rtBox.SelectionFont = newFont
End Sub
Private Sub Italics_Text(rtBox As RichTextBox)
Dim newStyle As FontStyle
If rtBox.SelectionFont.Style = FontStyle.Italic Then
newStyle = rtBox.SelectionFont.Style And Not FontStyle.Italic
Else
newStyle = rtBox.SelectionFont.Style Or FontStyle.Italic
End If
Dim newFont As New Font(rtBox.SelectionFont.Name, rtBox.SelectionFont.Size, newStyle)
rtBox.SelectionFont = newFont
End Sub
Private Sub Underline_Text(rtBox As RichTextBox)
Dim newStyle As FontStyle
If rtBox.SelectionFont.Style = FontStyle.Underline Then
newStyle = rtBox.SelectionFont.Style And Not FontStyle.Underline
Else
newStyle = rtBox.SelectionFont.Style Or FontStyle.Underline
End If
Dim newFont As New Font(rtBox.SelectionFont.Name, rtBox.SelectionFont.Size, newStyle)
rtBox.SelectionFont = newFont
End Sub
Private Sub Reset_Text(rtBox As RichTextBox)
Dim newFont As New Font(rtBox.SelectionFont.Name, rtBox.SelectionFont.Size, FontStyle.Regular)
rtBox.SelectionFont = newFont
End Sub
Private Sub Strikeout_Text(rtBox As RichTextBox)
Dim newStyle As FontStyle
If rtBox.SelectionFont.Style = FontStyle.Strikeout Then
newStyle = rtBox.SelectionFont.Style And Not FontStyle.Strikeout
Else
newStyle = rtBox.SelectionFont.Style Or FontStyle.Strikeout
End If
Dim newFont As New Font(rtBox.SelectionFont.Name, rtBox.SelectionFont.Size, newStyle)
rtBox.SelectionFont = newFont
End Sub
与往常一样,非常感谢您的帮助!
答案 0 :(得分:1)
这是我最终解决我的问题FWIW的方式 我没有尝试所有样式组合,而是使用了Sylverac将样式发送到字符串的技巧,只是在返回的字符串中检查相关样式的关键字等。
代码:
Point
答案 1 :(得分:0)
男人这是一个棘手的问题。
我复制了您的代码并在Bold_Text
方法中添加了断点。我发现你的If语句没有检查Bold and Underline
条件。这是我的意思代码:
If rtBox.SelectionFont.Style = FontStyle.Underline Then
当我添加断点时,在尝试删除粗体时,它跳过了这个条件并转到了Else
子句,因为你只检查它是否是粗体,而不是粗体和下划线。在If语句之前添加一个MessageBox,以查看它是否检测到如下所示的粗体和下划线样式:
MessageBox.Show(rtBox.SelectionFont.Style.ToString)
这表明rtBox.SelectionFont.Style
设置为"粗体,下划线"。
要修复它,我使用了以下代码:
If (rtBox.SelectionFont.Style = FontStyle.Bold) OrElse (rtBox.SelectionFont.Style = (FontStyle.Bold Or FontStyle.Underline)) Then
请参阅this link了解更多信息。
FontStyle枚举是一个标志枚举,因此您可以组合值(使用VB.NET中的Or运算符...